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UNIX Date function with -d options

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# 1  
Old 03-04-2016
UNIX Date function with -d options
Hi ,

I couldn't understand how this program works. Can somebody please explain it to me.

Code:
DT=`date -d "1 day"`  # This part I understand
echo ${DT/ */}  # How this works
echo ${DT/* /}

# 2  
Old 03-04-2016
Hello LoneRanger,

Following is the detailed information on same.

1st: When you run command DT=`date -d "1 day"`, whose value you could see as follows.
Code:
echo $DT
Sat Mar 5 06:52:33 EST 2016

2nd: Now command echo ${DT/ */}, will remove everything from the line Sat Mar 5 06:52:33 EST 2016 from 1st space to till end of line.
3rd: Now command echo ${DT/* /}, will remove everything from the starting from line to till last occurrence of space in line.


Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
looney
# 3  
Old 03-04-2016
Look into your shell's man page (e.g. man bash) for parameter expansion / pattern substitution.
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