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Text manipulation with sed/awk in a bash script

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# 8  
Old 01-21-2016
The sed code starts with s, the substitute command.
The following character / is a delimiter, followed by a Regular Expresson, a delimiter, and the substitution string. The substitution string is terminated by another delimiter (that can be followed by an option).
In a Regular Expression each . matches a character.
By a \( \) one can mark groups.
The first group contains the 3rd and 4th character, the second group contains the 5th and 6th character, ...
The reference to the first group is \1
The second group should be printed first, so the \2 is first in the substitution string. Followed by a -, followed by the third group, ...
This User Gave Thanks to MadeInGermany For This Post:
dendenyc
# 9  
Old 01-21-2016
Quote:
Originally Posted by MadeInGermany
The sed code starts with s, the substitute command.
The following character / is a delimiter, followed by a Regular Expresson, a delimiter, and the substitution string. The substitution string is terminated by another delimiter (that can be followed by an option).
In a Regular Expression each . matches a character.
By a \( \) one can mark groups.
The first group contains the 3rd and 4th character, the second group contains the 5th and 6th character, ...
The reference to the first group is \1
The second group should be printed first, so the \2 is first in the substitution string. Followed by a -, followed by the third group, ...
Great explain, thanks alot.
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