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Print hex Ip address in decimal format inside awk script

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# 1  
Old 12-07-2015
Print hex Ip address in decimal format inside awk script
Hi to all,

May someone help me with the following.

The awk script below is part of a bigger awk script, and this part attempts to print an Ip address that is in hex format in decimal format. I'm trying with following code but
I'm getting 0.0.0.0 and the correct answer is 192.168.140.100

Code:
echo "d djjd:C0 A8 8C 64 00 00 00" | 
awk '{a=gensub(/.+:(..) (..) (..) (..).+/,"\\1 \\2 \\3 \\4","g");split(a,b);printf("%d.%d.%d.%d","0x"b[1],"0x"b[2],"0x"b[3],"0x"b[4])}'
0.0.0.0

Thanks in advance,
# 2  
Old 12-07-2015
Hi, see https://www.unix.com/302618249-post4.html
Regards.
# 3  
Old 12-07-2015
Why that complicated? Try
Code:
echo "d djjd:C0 A8 8C 64 00 00 00" |  awk '{sub (/:/," "); printf("%d.%d.%d.%d\n","0x"$3,"0x"$4,"0x"$5,"0x"$6)}'
192.168.140.100

---------- Post updated at 17:46 ---------- Previous update was at 17:39 ----------

Or
Code:
echo "d djjd:C0 A8 8C 64 00 00 00" |  awk '{X="0x"; sub (/:/," "); printf("%d.%d.%d.%d\n", X$3, X$4, X$5, X$6)}'
192.168.140.100

# 4  
Old 12-07-2015
Thanks disedorgue/RudiC.

I've tried both solutions of RudiC and with both I get 0.0.0.0. I've tried in GNU/Linux, Cygwin and CentOS 6.7.

I'm not sure why.

Thanks in advance
# 5  
Old 12-07-2015
Post your attempts.
# 6  
Old 12-07-2015
When I try with your solutions there is no more as output like 0.0.0.0

When I try with my script I get the same 0.0.0.0.

I've done the following tests and it works when don't go the commas and work with single comma and without comma. It seems the issue begins when I try to convert variables that contain hex values.

Code:
$ echo "d djjd:C0 A8 8C 64 00 00 00" | awk '{sub (/:/," "); printf("%d", 0xC0)}'
192
$ echo "d djjd:C0 A8 8C 64 00 00 00" | awk '{sub (/:/," "); printf("%d", '0xC0')}'
192
$ echo "d djjd:C0 A8 8C 64 00 00 00" | awk '{sub (/:/," "); printf("%d", "0xC0")}'
0
$ awk 'BEGIN{Z=C0; printf("%d", 0xZ)}'
0

# 7  
Old 12-07-2015
Above is diametrically opposed to what I get:
Code:
echo "d djjd:C0 A8 8C 64 00 00 00" | awk '{sub (/:/," "); printf("%d", 0xC0)}'
0
echo "d djjd:C0 A8 8C 64 00 00 00" | awk '{sub (/:/," "); printf("%d", '0xC0')}'
0
echo "d djjd:C0 A8 8C 64 00 00 00" | awk '{sub (/:/," "); printf("%d", "0xC0")}'
192

The variables or constants need to be string "0x" plus a hex value string, e.g. "C0". That why your fourth attempt doesn't work - Z is assigned the number 0.
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