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Shell Programming and Scripting

Store result variable

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# 1  
Old 11-26-2015
Store result variable
Friends have the following problem:

Code:
cat $PATH_DAT/mr.txt | nawk  'BEGIN {
                CantPnt=0;
                NumReg=0;
                FS="|"
              }
              {
                NumReg++
                CantPnt=CantPnt+int($2)
              }
END{
        printf ("%d|%d",NumReg,CantPnt)
}
' > TmpValida.Tmp

this perfect function code without problem and the result is in the file TmpValida.Tmp

you need to do is save the result in a variable and not in the file
# 2  
Old 11-26-2015
Hello tricampeon81,

Could you please try following and let me know if this helps you. I haven't tested it though.
Code:
VAR=`nawk  'BEGIN {CantPnt=0;NumReg=0;FS="|"} {NumReg++; CantPnt=CantPnt+int($2)} END{printf ("%d|%d",NumReg,CantPnt)}' $PATH_DAT/mr.txt`

You could then print the value of variable named VAR by doing echo $VAR.

Thanks,
R. Singh
# 3  
Old 11-26-2015
Quote:
Originally Posted by RavinderSingh13
Hello tricampeon81,

Could you please try following and let me know if this helps you. I haven't tested it though.
Code:
VAR=`nawk  'BEGIN {CantPnt=0;NumReg=0;FS="|"} {NumReg++; CantPnt=CantPnt+int($2)} END{printf ("%d|%d",NumReg,CantPnt)}' $PATH_DAT/mr.txt`

You could then print the value of variable named VAR by doing echo $VAR.

Thanks,
R. Singh
this function but the result is not the same to remove the CAT

# 4  
Old 11-26-2015
Please show the differences, then!
This User Gave Thanks to RudiC For This Post:
tricampeon81
# 5  
Old 11-26-2015
Quote:
Originally Posted by tricampeon81
this function but the result is not the same to remove the CAT
I am so sorry!!!
I have not seen that replaced the cat at the end !!
function perfect !!!!!
was what nesecitaba !!!

This product is perfect !!!!

---------- Post updated at 08:00 AM ---------- Previous update was at 07:59 AM ----------

I tried it and it works perfect

---------- Post updated at 08:33 AM ---------- Previous update was at 08:00 AM ----------

hat friendly look that code this variable turned keeps this value:
Code:
Nawk `VAR = 'BEGIN {CantPnt = 0; SET- # = 0; FS =" | "} {SET- # ++; CantPnt CantPnt + = int ($ 2)} END {printf ("% d |% d" SET- #, CantPnt)} '$ PATH_DAT / mr.txt`

Code:
Departure:

VAR = 10 | 500

now I need to keep the 10 in a variable and another variable 500 I tratandod and use split but not me
# 6  
Old 11-26-2015
With a recent bash, you can try a here string:
Code:
IFS="|" read VAR1 VAR2 <<< $(nawk '... ' ...)

or a here document:
Code:
IFS="|" read VAR1 VAR2 << EOF
 $(nawk '... ' ...)
EOF

---------- Post updated at 14:56 ---------- Previous update was at 14:55 ----------

You can drop the IFS definition if you don't print the "|" in the awk output but use " " instead.
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