I'm not real familiar with sed, but I need to capture the year this directory path. Here's what I have so far. I'm able to capture the run name, but I want the only the year that's within the run name. How can I do this?
Code:
TSP_FILEPATH_PLUGIN_DIR=/Home/Auto_user_124-451-12October2015_WH15-0186_YN_531_504/plugin_out/variantCaller_out.981/
RUN=`echo ${TSP_FILEPATH_PLUGIN_DIR} | sed -e 's#.*/Home/\(.*\)/plugin_out/.*#\1#g'`;
If you're using a shell that performs parameter expansions required by the POSIX standards, there are ways to do this entirely in the shell without invoking sed twice. For example:
Code:
#!/bin/ksh
TSP_FILEPATH_PLUGIN_DIR=/Home/Auto_user_124-451-12October2015_WH15-0186_YN_531_504/plugin_out/variantCaller_out.981/
RUN=${TSP_FILEPATH_PLUGIN_DIR##*/Home/}
RUN=${RUN%%/*}
YEAR=${RUN##*[yhletr]}
YEAR=${YEAR%%_*}
printf '%s="%s"\n' RUN "$RUN" YEAR "$YEAR"
If it isn't obvious, the match against the letters "y", "h", "l", "e", "t", and "r" is a search for the last letter in an English month name. You could also use:
Code:
YEAR=${RUN##*[[:lower:]]}
to get the same results. Of the two, I chose the one requiring less typing.
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http://i51.tinypic.com/2eg4kdd.png
So that's taking a URL and splitting it into URL,TLD & Filename. Any help on how I can do this is much appreciated.
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Hi guys,
I have been trying to play with sed to accomplish this but I just can't quite get it right.
I need to be able to remove the year from a string held in a variable in my bash script.
The string may have multiple words but always ends with a year such as (2009)
for example:
... (2 Replies)
