Shell Programming and Scripting

Why don't you give it a try (by just printing the resulting file names)? It will make find search only the uppermost directory.

As I said before, use the for loop in the shell if you want to use the date in the filename to determine which files are a year old and use find if you want to use the last modification time of the file to determine which files are a year old.

The shell for loop I provided only looks at files in the current directory. If you want to use find and only want to look at files in the current directory, you could try what RudiC suggested:

Code:

find Ft*.*.log -mtime +364 -exec echo rm {} +

but, if there are LOTS of files matching that pattern, you might fail with an E2BIG error. And, if there are subdirectories in the current directory that have the same filename format as the log files you want to process, it will search those directories for log files to process. If either of these things is a problem you can avoid both of them with:

Code:

find . \( -type d ! -name "." -prune \) -o  -name 'Ft*.*.log' -mtime +364 -exec echo rm {} +

Don,
Apologize for the delayed response, struck in another issue.
The KSH ran as expected for me. Thanks a lot ..

And may be this is very basic to ask... just want to know about this command.

Code:

EDD=$(($(date +%Y%m%d) - 10000))

how did we arrive at 10000. wanted to learn this calculation, as in case if i need to modify this script to look for files before a month or so.

Thanks in advance !!!

Code:

date +%Y%m%d
20151022

is just a number. Subtracting 10000 will result in a number representing one year ago. (May fail on certain dates, e.g. 29. Feb.)

Thanks Rudi..

Got the logic.. Thanks Again Rudi..

I wasn't trying to create a valid date a year ago; I was just looking for a number representing a year ago that we can compare to a number representing some other arbitrary date. Except for leap days, the number produced is a valid representation of the number produced in the same way for the date exactly one year ago.

And, when run on a leap day, it will still yield a value that can be compared against a valid date string approximately one year ago and get reasonable results from a numeric comparison. The numeric representation of March 1 of the previous year will be greater than the numeric representation of February 29th a year ago even though there was no February 29 a year ago. And the numeric representation of February 28 of the previous year will still be less than the representation of February 29th a year ago even though there was no February 29 a year ago.

Thank you Don..Understood.