Shell Programming and Scripting

Hello
I have a requirement where I need to replace space :61 with !@ :61
Source
:60F:123 :61:151 :61:151 :61:15101

Target
:60F:123 :61:151!@:61:151!@:61:15101

I cant use [:space:] and [:blank:] command as I don't want the tab to be converted .

commands not working :

Code:

sed 's/ \(:61:\)/!#\2/g' file1 > file2
sed 's/ \(:61:\)/!#\(:61:\)/g' file1 > file2

Thanks

Hello kamijia83,

Could you please try following and let us know if this helps you.

Code:

echo ":60F:123 :61:151 :61:151 :61:15101" | sed 's/ :61/!@:61/2;s/ :61/!@:61/2'

Output will be as follows.

Code:

:60F:123 :61:151!@:61:151!@:61:15101

Also this solution is changing the 2nd and 3rd occurrences of :61 as per your sample input, if you have more rules related to your input please do let us know with complete same input and expected output.


Thanks,
R. Singh

Would that work?

Code:

sed 's/ \(:61\)/!@\1/2g' file1 > file2

Hi Ravinder

Thanks for the reply !! Actually there can be any number of :61 tags

Between :60F tag and : 61 I have a TAB

Code:

:60F:123 :61:151

and then I can have any number of 61 tags with spaces between them

There are a few problems with your attempts. You say you want to change a <space> to !@, but your sed substitutions contain !# instead of !@. You have only one parenthesized expression but you use \2 instead of \1 to refer to what was matched by that parenthesized expression. And, your 2nd sed command is inserting unwanted parentheses in the output.

Any of the following should work:

Code:

sed 's/ \(:61:\)/!@\1/g' file1 > file2
sed 's/ \(:61:\)/!@:61:/g' file1 > file2
sed 's/ :61:/!@:61:/g' file1 > file2

The last of these is the shortest and simplest, so I would probably use it.

Thanks a lot Don for your help and making me understand my mistake !!!Really appreciate your help

Have a nice weekend !!

---------- Post updated at 11:32 AM ---------- Previous update was at 11:30 AM ----------

Thanks a lot Aia and Ravinder for your quick responses !!
Was able to resolve the issue