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Issue using empty variable in grep command

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# 8  
Old 10-05-2015
Issue using empty variable in grep command
I don't think we can swap lines 2 and 3 as 'do' for first "for loop" is further down, unless I didn't get what you wanted me to do.

Actually below code i.e., for variable 'i' is in between backticks
Code:
` `

Code:
for i in `
    for DISK in `awk '/disk/ {print substr($1, 7)}' /tmp/list.out`
    do
        if [ -z "$DISK" ]
        then
           lspv | awk '{print$1}'
        else
           lspv | awk '{print$1}' | grep -vw "$DISK"
        fi
    done
`

"for loop" for variable 'i' continues here
Code:
do
 .......
done

# 9  
Old 10-05-2015
You might want to add a space between the [ICODE]'{print $1}'[/ICODE]'s.
Edit: nevermind..
Last edited by sea; 10-05-2015 at 05:33 PM..
# 10  
Old 10-05-2015
ssue using empty variable in grep command
I got the nested "for loop" error part working by using
Code:
$( )

instead of backticks
Code:
` `

BUT cannot exclude all of the values at once coming from /tmp/list.out using grep -vw option in line 8.

Code:
for i in `
    for DISK in $( awk '/disk/ {print substr($1, 7)}' /tmp/list.out` )
    do
        if [ -z "$DISK" ]
        then
           lspv | awk '{print$1}'
        else
           lspv | awk '{print$1}' | grep -vw "$DISK"
        fi
    done
`
do
  .....
done

Last edited by mbak; 10-05-2015 at 08:13 PM.. Reason: typo
# 11  
Old 10-06-2015
What do you mean by
Quote:
BUT cannot exclude all of the values at once coming from /tmp/list.out using grep -vw option in line 8.
?
# 12  
Old 10-06-2015
Basically I'm just trying to exclude the values of /tmp/list.out from 'lspv' output which is line 8.
# 13  
Old 10-15-2015
What is /tmp/list.out?
How is it created?
Can you give an example?
# 14  
Old 10-17-2015
I'm separating disks coming off a particular XIV storage array and redirecting output to /tmp/list.out as below

Code:
lsdev -Cc disk |grep 2810 |grep awk'{print$1}' > /tmp/list.out

and
Code:
cat /tmp/list.out
hdisk0
hdisk50
hdisk115

.
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