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Copy files with different extensions and same name

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# 1  
Old 09-15-2015
Copy files with different extensions and same name
Hi,

i have two folders. Folder A has 1000+ files with just images named like :

Code:
01012015.png
01022015.png

etc. Folder B has much more files, part of them with same name as png files folder others not. Instead of folder A wich are only images, these are audio wav files.

I need to copy the second folder with just the files that have the same name, but dfferent extension. from example if in folder A i have 01012015.png and in folder B i have 01012015.wav , just to copy the second files inside the A folder , doing it manually will be too long to do it.

Any help will be welcome.

Regards
# 2  
Old 09-15-2015
Run this on your command line with appropriate modifications:

Code:
for f in /path/to/folderA; do filename=$(echo $f | sed -e 's/.*\///' -e 's/\..*//'); cp /path/to/folderB/${filename}.wav /path/to/folderA/; done

# 3  
Old 09-15-2015
What have you got so far? You could:-
  • List all the files less the .png in folder A into a file, say /tmp/folderA.lst
  • List all the files less the .wav in folder B into a file, say /tmp/folderB.lst
To list file numbers in folder A that are also in folder B, use:-
Code:
grep -f /tmp/folderA.lst /tmp/folderB.lst

To list file numbers in folder A that are not in folder B, use:-
Code:
grep -vf /tmp/folderA.lst /tmp/folderB.lst

THat would give the the appropriate list, and you can then do whatever is required from that.

Does that get you started?


Robin
# 4  
Old 09-16-2015
Hello,

thank you for your time. I've checked again and the names are different. In folder A I have 20150730_091113.wav-image.png , in the other folder I have 20150730_091113.wav . I've tried with your method, using *.lst files but they didn't match using grep -f . Maybe I should even all names or is there another solution?

Thanks in advance

regards
Last edited by rbatte1; 09-16-2015 at 06:12 AM.. Reason: Added ICODE tags for filenames and commands
# 5  
Old 09-16-2015
How did you generate the two files? You would need to be in the correct directory when you run the list command.

Can you paste a sample of the two files generated?



Robin
# 6  
Old 09-16-2015
Hello,

first i've renamed the images with this code :

Code:
for f in *.wav-image.png;do
mv -- "$f" "${f%.wav-image.png}.png"
done

so now i've got two folders . Folder A has png files with this extensions :

Code:
20150811_063330.png

Folder B has wav files with this extension :
Code:
20150811_063330.wav

i've tried your method creating .lst files using this command :

Code:
cat imagesdir/*  > listA.lst

and

Code:
cat wavsdir/*  > listB.lst


then

Code:
 grep -f listA.lst listB.lst


and it ends with a :

Code:
grep: Unmatched [ or [^

regards
# 7  
Old 09-16-2015
You would be better to create the files like this:-
Code:
cd imagesdir
ls | cut -f1 -d "." > ../listA.lst            # Important not to write to the current directory
cd ..

cd wavsdir
ls | cut -f1 -d "." > ../listB.lst            # Important not to write to the current directory
cd ..

What you have done is to write the contents of all the files into listA.lst & listB.lst respectively rather than the list of filenames.

The above approach has the cut in place to trim off the end of each file name, so you should end up with two files that list what would be the common parts of the names that you are looking to compare. This assumes that there are no files with a dot in the part you want to compare.

Using the grep commands would then list the common (or missing) files that you are interested in and you can build your required commands from in a loop, obviously adding back on the .png or .wav as appropriate.


Does that help?

Robin
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