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Search for a string at a particular position and replace with blank based on position

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# 1  
Old 09-08-2015
Search for a string at a particular position and replace with blank based on position
Hi,

I have a file with multiple lines(fixed width dat file). I want to search for '02' in the positions 45-46 and if available, in that lines, I need to replace value in position 359 with blank. As I am new to unix, I am not able to figure out how to do this. Can you please help me to achieve this?
# 2  
Old 09-08-2015
Any attempts from your side? Which OS and shell are you using?
# 3  
Old 09-08-2015
I tried with sed but it didnt work. Am using korn shell.
# 4  
Old 09-08-2015
What sed command did you try?
# 5  
Old 09-09-2015
Quote:
Originally Posted by Pradhikshan
Hi,

I have a file with multiple lines(fixed width dat file). I want to search for '02' in the positions 45-46 and if available, in that lines, I need to replace value in position 359 with blank. As I am new to unix, I am not able to figure out how to do this. Can you please help me to achieve this?
Do you have Perl?
Try:

Code:
perl -ple 'substr $_, 358, 1," " if (substr $_, 44, 2) == "02";' Pradhikshan.file

I am assuming when you mention positions you're starting counting at 1, which is 0 for Perl.

perl -ple: # invoke the perl command at the command line with automatic printing of each line
substr $_, 358, 1," ": # replace the 359th character with blank (starts counting at 0) [if ...]
if (substr $_, 44, 2) == "02": # ... if characters 45th and 46th make the string 02; (starting at 45th position take 2 characters).
Last edited by Aia; 09-09-2015 at 12:40 AM..
# 6  
Old 09-09-2015
I tried the below sed command.

Code:
sed '/(^.\{44\}\)02/s/\(^.\{358\}\).\{1\}\(.*\)/\1 \2/'

but didnt work out.
Last edited by Don Cragun; 09-16-2015 at 03:32 AM.. Reason: Add CODE tags.
# 7  
Old 09-09-2015
Would that do it?
Code:
sed 's/\(^.\{44\}02.\{312\}\).\(.*$\)/\1 \2/'
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