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Shell Programming and Scripting

Print between pattern without spaces

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# 1  
Old 08-20-2015
Print between pattern without spaces
I seem to have hit a curious problem where sed and awk based regex do not seem to work. Perhaps I am missing a switch to look within the same line and not across lines.

I have input as follows:

Code:
2E3DD452DA34CB2E9D003E934CC5E57843F5AF82.04713CF0013BBB0731441B693992F2E625D33589&range=0-1000&reef=121816
2E3DD452DA34CB2E9D003E934CC5E57843F5AF82.04713CF0013BBB0731441B693992F2E625D33589&range=1000-10000&reef=121817

I want to print text between the range tag and the &. However
Code:
sed -n '/range/,/reef/p'

does not seem to work in this case. Do I need to escape things differently here?

The expected output is
Code:
0-1000
1000-10000

.

Thanks.
# 2  
Old 08-20-2015
Hello Jamie_123,

Following may help you in same.
Code:
awk '{match($0,/\=.*\&/);print substr($0,RSTART+1,RLENGTH-2)}' Input_file

Output will be as follows.
Code:
0-1000
1000-10000

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
jamie_123
# 3  
Old 08-20-2015
Hi RavinderSingh13,

Thanks for the quick response. The solution seems to be very specific, depending on = and numbers. It seems to find other matches in the larger file that I have. Is a general solution based on range and reef possible?

---------- Post updated at 03:17 PM ---------- Previous update was at 03:13 PM ----------

I figure something like this might work for me. I am using RSTART+6 to exclude range and the +15 is just to get everything until the end of the line.

Code:
awk '{match($0,/range/);print substr($0,RSTART+6,RSTART+15)}' | awk 'BEGIN { FS = "&" } ; { print $1 }'

Thanks!
# 4  
Old 08-20-2015
Hello Jamie_123,

Following may help you to be more specific. Let me know if this helps.
Code:
awk '{match($0,/\&range.*\&reef/);print substr($0,RSTART+7,RLENGTH-12)}'  Input_file

Output will be as follows.
Code:
0-1000
1000-10000

This User Gave Thanks to RavinderSingh13 For This Post:
jamie_123
# 5  
Old 08-21-2015
Or:
Code:
sed -e 's/^.*range=//' -e 's/&.*//'

or even:
Code:
sed -ne 's/^.*range=\([^&]*\)&.*$/\1/p'

which will skip lines w/o "range=" entries.
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