Im facing a weird behavior storing regular expression in a vaiable.
Let us consider
when I echo the above variable its displaying below which is file
but when I create a file with name CTP02_1234.tar, and when I echo $file_name its showing CTP02_1234.tar not CTP02_[0-9]*tar.gz Why this issue ? How to overcome ? I need to need to use this in grep
My scenario is, to find the number of files which are of type CTP02_[0-9]*.tar in a folder.
Appreciate your help
Thanks
Last edited by Don Cragun; 08-14-2015 at 05:39 PM..
Reason: Add CODE and ICODE tags.
Note that you don't grep a folder (usually called a directory in UNIX and Linux environments). The grep utility searches for text in the contents of text files (not directories on most systems).
If you're trying to count the number of files in a directory that have names matching the globbing pattern stored in your shell variable named (confusingly) file_name, you could try something like:
which should work as long as there aren't any newline characters in your file names. If you have users who create filenames containing newline characters, or if you just want to use shell built-ins, a fast way to get what you want is:
(assuming that you aren't using command line arguments or have already gathered what you need from them, and assuming that at least one file matching your pattern exists) or, if there might not be any matching files (but there also might be a file with a name that is your pattern):
I'm trying to use a series of regular expressions as variables but can't get it to behave properly.
You can see below what I'm trying to do.
Here with lowercase a-z and the same with uppercase, numbers 0-9 and again with a set of special characters, without having to type out every single... (3 Replies)
Hello All,
I'm trying to extract the lines between two consecutive elements of an array from a file.
My array looks like:
problem_arr=(PRS111 PRS213 PRS234)
j=0
while } ]
do
k=`expr $j + 1`
sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt
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i have a command line like this in csh script
grep -i "$argv$"
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Hi All,
I have a sftp session log where I am transferring multi files by issuing "mput abc*.dat". The contents of the logfile is below -
#################################################
Connecting to 10.75.112.194...
Changing to: /home/dasd9x/testing1
sftp> mput abc*.dat
Uploading... (7 Replies)
Hi all,
How am I read a file, find the match regular expression and overwrite to the same files.
open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat";
open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat";
while (<DESTINATION_FILE>)
{
# print... (1 Reply)
Hi All,
Below is a sample code:
print "Enter the Name: ";
my $Name = <>;
print "Word is $Name";
open (FH,"AIDNameList.txt");
while (<FH>)
{
my $line;
print "Word is $Name";
for $line(<FH>)... (12 Replies)
Hi,
I have this script:
awk -v va=45 '$0~va{print}' flo2
That returns: "4526745 1234 " (this is the only line of the file "flo2".
However, I would like to get "va" to match the begining of the line, so that is "va" is different than 45 (eg. 67, 12 ...) I would not have any output. That... (3 Replies)
Anyone know how I will use awk's variable in a regular expression?
This line of code of mine is working, the value PREMS should be a variable:
awk '$1 ~ /PREMS/ { if(length(appldata)+2 >= length($1)) print $0; }' appldata=$APPLDATA /tmp/file.tmp
The value of APPLDATA variable is PREMS.
... (2 Replies)
hello,
I use AIX with ISM PILOT, I want to match something with a varible like this :
$variable = 10 #this variable is the number of the job
"$variable STARTED" # the pattern
how can use this variable to match it with the word STARTED
Tanks (0 Replies)