Shell Programming and Scripting

How do you write a code in ksh ??

Enter the start date: 20060228
d0 = 20060228;

2. Check for 7 days of report list 1 day after the d0
d1 = 20060301
d2 = 20060302
d3 = 20060303
d4 = 20060304
d5 = 20060305
d6 = 20060306

then cat d0.log d1.log d2.log d3.log d4.log d5.log d6.log > 7days.log
if missing one day will give a warning missing date ???
and lines = `cat 7 days.log | wc -l`

Example
$weeklycount 20060228
$lines=3650


Thanks

hi
Genrating next date requires bit of too many ifs any way here si what i would plan to do .hope it helps. I have just given you idea as how you can proceed.
Once done post the code )))

#!bin/ksh

nextDate( ){
MM=`echo "$VAR1" | awk '{print substr($VAR1,1,2)}'`
DD=`echo "$VAR1" | awk '{print substr($VAR1,3,2)}'`
YYYY=`echo "$VAR1" | awk '{print substr($VAR1,5,4)}'`
# Do all your evaluations here
# Increase value of Day
DD=`expr $DD + 1`
If [[ $DD >31 ]] # for odd months
#increment month
If [[ $DD > 30 ]] # for even months
#increment month

#Same logic applies for year
#Dont forget leap year and February month

}

VAR1=20060101
d0=$VAR1
d1=nextDate $d0
d2=nexDate $d1
..
...
......

d7=nexDate $d6


if missing one day will give a warning missing date ???
Do cat one after another

cat d0.log > 7days.log
if [[$?!=0]]
echo $d0 file missing
#append rest data
cat d1.log >> 7days.log
if [[$?!=0]]
echo $d1 file missing


....
...
Do the same for rest of files

and Finally

lines = `cat 7 days.log | wc -l`