Shell Programming and Scripting

I have input file as below I need to check for a pattern and if it is there in file then I need to print all the lines below BEGIN and END keyword. Could you please help me how to get this in AIX using sed or awk.

Input file:

Code:

ABC
******** BEGIN *****
My name is Amit.
I am learning unix.
***** END *****
***** BEGIN *****
My name is Rahul.
***** END *****
XYZ

If I am looking for Amit then Output should be

Code:

******** BEGIN *****
My name is Amit.
I am learning unix.
***** END *****

If I am looking for Rahul then Output should be

Code:

***** BEGIN *****
My name is Rahul.
***** END *****

If I am looking for XYZ then Output should be nothing.


From below command I am able to get all the data between two keyword but not able to grep the data.

Code:

sed -n '/BEGIN/,/END/p'