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Print all lines between two keyword if a specific pattern exist

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Top Forums Shell Programming and Scripting Print all lines between two keyword if a specific pattern exist
# 8  
Old 08-14-2015
Thanks bakunin for superb explanation Smilie It really helped me to understand the each option used in command.

Thanks anbu23 and all for your inputs.It was really helpful.
# 9  
Old 08-14-2015
[QUOTE=protocomm;302952163]
Quote:
Originally Posted by anbu23
Code:
$ awk ' /BEGIN/,/END/ { str = str ?  str "\n" $0 : $0 } /END/ { if( str ~ /Amit/ ) { print str }; str = "" } ' file
******** BEGIN *****
My name is Amit.
I am learning unix.
***** END *****

Could you explain the part
Code:
str = str ?  str "\n" $0

of your command line please, it's confuse for me.
I've understood that for each block /BEGIN/,/END/ you do this { str = str ? str "\n" $0 : $0 }, i know the result but it's not clear for me
Thx.
The condition ? trueaction : falseaction exists in awk like in C.
str gets the concatentation of str "\n" $0 if str is not null (undefined, empty, or 0), otherwise it gets $0.
$0 is the entire line.
BTW it will misbehave if the line is 0; better is { str = (str != "") ? (str "\n" $0) : $0 } but still has problem with empty lines.
That's why I prefer the { str = str sep $0; sep="\n" } method.
These 2 Users Gave Thanks to MadeInGermany For This Post:
anbu23 protocomm
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