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Replace pattern from nth field from a file

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# 1  
Old 07-26-2015
Replace pattern from nth field from a file
Code:
$ cat /cygdrive/d/Final2.txt
1,A ,Completed, 07.03_23.01 ,Jun 30 20:00
2,BBB,Pending,,
3,CCCCC,Pending,,
4,DDDDD,Pending,,
5,E,Pending,,
6,FFFF,Pending,,
7,G,Pending,,


In the above file 4th field is date which is in MM.DD_HH.MIN format and I need to convert it to as it is there in 5th columns.

Any idea how I can do that in unix shell script with sed or awk or any other command ?
Last edited by Don Cragun; 07-26-2015 at 08:01 AM.. Reason: Add CODE and ICODE tags.
# 2  
Old 07-26-2015
Quote:
Originally Posted by Amit Joshi
Code:
$ cat /cygdrive/d/Final2.txt
1,A ,Completed, 07.03_23.01 ,Jun 30 20:00
2,BBB,Pending,,
3,CCCCC,Pending,,
4,DDDDD,Pending,,
5,E,Pending,,
6,FFFF,Pending,,
7,G,Pending,,


In the above file 4th field is date which is in MM.DD_HH.MIN format and I need to convert it to as it is there in 5th columns.

Any idea how I can do that in unix shell script with sed or awk or any other command ?
Is this a homework assignment? There are special rules for homework submissions.

If this isn't homework, I still don't understand what you're trying to do. The 4th field in most of your input lines is an empty string (not in the format MM.DD_HH.mm) and the one line that does have something like that also has leading and trailing <space>s. What do you mean by "convert it to as it is there in 5th columns"? Are you saying that you want the output to be:
Code:
1,A ,Completed,Jun 30 20:00,Jun 30 20:00
2,BBB,Pending,Jun 30 20:00,
3,CCCCC,Pending,Jun 30 20:00,
4,DDDDD,Pending,Jun 30 20:00,
5,E,Pending,Jun 30 20:00,
6,FFFF,Pending,Jun 30 20:00,
7,G,Pending,Jun 30 20:00,

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