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Print specific field when condition met

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# 1  
Old 07-22-2015
Print specific field when condition met
Hi All,

Seeking for your assistance to print all the specific field when the condition met.
Code:
Ex:
file1.txt
1|203|3|31243|5341|6452|623|22|00|01
3|45345|123214|6534|3423|6565|643|343|232|10

if field 1 = 1 and field 3 = 3 and field 5 = 5341 and field 6 = 6452
it will print from $1 to $10.

What i did was i used awk but it output first all $1 record then next is all $2 record which is wrong.

Code:
#!/bin/sh

type1=`awk -F "|" '{print $1}' file1.txt`
type2=`awk -F "|" '{print $3}' file1.txt`
type3=`awk -F "|" '{print $5}' file1.txt`
type4=`awk -F "|" '{print $6}' file1.txt`

if [[ $type1 == "1" && $type2 == "3"  && $type3 == "5341" && $type4 == "6452"  ]]; then
awk -F "|" '{print $1,$2,$3,$4,$5,$6,$7,$8,$9,$10}'
fi

Please advise,

Thanks,
# 2  
Old 07-22-2015
Hello znesotomayor,

Following may help you in same.
Code:
cat file23
1|203|3|31243|5341|6452|623|22|00|01
3|45345|123214|6534|3423|6565|643|343|232|10

awk -F"|" '($1==1 && $3==3 && $5==5341)' file23

Output will be as follows.
Code:
1|203|3|31243|5341|6452|623|22|00|01

Hope this helps.


Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
znesotomayor
# 3  
Old 07-22-2015
Thanks Mr. R. Singh. It helps me a lot.
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