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How do i replace a word ending with "key" using awk excpet for one word?

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# 1  
Old 07-20-2015
How do i replace a word ending with "key" using awk excpet for one word?

echo {mbr_key,grp_key,dep_key,abc,xyz,aaa,ccc} | 
awk 'gsub(/^[grp_key,]|abc,|[key;]$/,"") {print}'

Required output

# 2  
Old 07-20-2015
echo mbr_key,grp_key,dep_key,abc,xyz,aaa,ccc | awk '/grp_key/ {print;next}; /abc|key/ {next}1' RS=, ORS=,

The braces cause brace expansion in bash; if needed, additional action must be taken.
# 3  
Old 07-20-2015
How the input looks like? Is it CSV as you shown? located where? from file , string or something else?
# 4  
Old 07-20-2015
Hi clx ,
You could say it is a string it is not CSV file.

Thanks i will try that , i forgot to add i am using korn shell.

# 5  
Old 07-20-2015
Hello 100bees,

Following may help you in same too.
 echo mbr_key,grp_key,dep_key,abc,xyz,aaa,ccc | awk -F, '{for(i=1;i<=NF;i++){if($i ~ /grp_key/){A=A?A OFS $i:$i};if($i !~ /key/){A=A?A OFS $i:$i}}} END{print A}' OFS=,

Output will be as follows.

Suggestion provided by RudiC is great but it will give at last a comma as ORS=, so above may fix that.

R. Singh
# 6  
Old 07-20-2015
% echo "{mbr_key,grp_key,dep_key,abc,xyz,aaa,ccc}" | perl -pe 's/\w+(?<!grp)_key,|abc,//g'

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