Shell Programming and Scripting

cp: omitting directory /root/test/data

#!/bin/bash
# strip a trailing /
src=${1%/}
dest=${2%/}
export PATH=/bin:/usr/bin:/usr/sbin:/sbin
# only a cd and pwd does a reliable pathname resolving
dpwd=$(cd "$dest"&& pwd)
spwd=$(cd "$src" && pwd)
if [ "$spwd" = "$dpwd" ]; then
  echo "src and dest are identical ($dpwd)"
  exit 1
fi

#find "$src" -depth -type f \( -name "IMG*" -o -name "*.???" \) -print |
# -o is or
# -a is default and can be omitted
# here \( -name "IMG*" -name "*.???" \) can be simplified
find "$src" -depth -type f -name "IMG*.???" -print |
while IFS="" read -r sname
do
  # strip the leading src and replace with dest
  ddir=$dest${sname#$src}
  # strip the trailing filename
  ddir=${ddir%/*}
  if [ "$ddir" != "$pddir" ]; then
    # "new" folder: 'find' can visit a folder several times
    pddir=$ddir
    echo mkdir -p "$ddir"
  fi
  # get the filename extension
  ext=${sname##*.}
  # compose the base dest filename
  dname=$ddir/${ddir##*/}
  # find a free number for dname
  CNT=0; while [ -e "$dname$((++CNT)).$ext" ]; do :; done
  echo cp "$sname" "$dname$CNT.$ext"
done