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File Manipulation

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# 1  
Old 07-06-2015
File Manipulation
Hi All!

Please I wonder if I can have some help using
Code:
awk

and
Code:
sed

to extract some information.

If I do
Code:
ls -lrt

in a directory, a list of files of months with their respective dates will appear, like files from january, February... etc, But if I want to list only files of 26th of June, I got stuck.
I have used
Code:
ls -lrt | awk '{if ($6 == "Jun")print $0}'

to list all files from June, but if I am required to list only files of June but with the date 26th, initially I´ve used
Code:
'{if ($7 == "26")print $0}

, but that piece of code can also show me files with date 26, but for the other months as well, which is not what I want.
Can you help
# 2  
Old 07-06-2015
Use && in your awk statement.

Code:
{ if  ( ( <condition> ) && ( <2ndcondition>) ) <operation> }

If both conditions are satisfied do the <operation>
# 3  
Old 07-06-2015
I am getting an error:

Code:
ls -lrt | awk {'(($6 == "Jun") && ($7 == "20")) print $0' }
 syntax error The source line is 1.
 The error context is
                {(($6 == "Jun") && ($7 == "20")) >>>  print <<<  $0
 awk: The statement cannot be correctly parsed.
 The source line is 1.
        awk: There is a missing } character.

# 4  
Old 07-06-2015
Hi,

you missed if as peasent suggested

Code:
ls -lrt | awk '{if(($6 == "Jun") && ($7 == "20")) print $0}'

Thanks
Venkat
This User Gave Thanks to venky.b5 For This Post:
fretagi
# 5  
Old 07-06-2015
thank you, if I wanted to add a third condition like list only files with a particular extension, would I just add that condition?
# 6  
Old 07-06-2015
Indeed you would, you can add as many as you need.
As for file extension, think about defining that before awk in ls statement with shell (e.g ls -lrt *.py | awk .. or alike)

You can test that on some dummy data and reach the conclusion yourself.

Regards
Peasant.
This User Gave Thanks to Peasant For This Post:
fretagi
# 7  
Old 07-06-2015
Quote:
Originally Posted by fretagi
thank you, if I wanted to add a third condition like list only files with a particular extension, would I just add that condition?
Code:
ls -lrt | awk '{if(($6 == "Jun") && ($7 == "20")) print $0}'

Since the default action is print $0 if not specified, that could be shortened as:
Code:
ls -lrt | awk '$6=="Jun" && $7=="20"'

which it will make it better if you want to add another condition like
Code:
ls -lrt | awk '$6=="Jun" && $7=="20" && $9 ~ /\.ext/'

These 2 Users Gave Thanks to Aia For This Post:
fretagi venky.b5
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