The purpose is to identify which user of the server has more process in a peak time of the day.
We identify that the server has a lot syscall between 10:00 am and 12:00 pm.
That is the reason to automation the process to collect information during this period ot time.
I though that the comand awk could the appropiate because it has a field capabilities per row but if you consider to create the script using another tool is welcome.
You can simplify your pipeline a little bit... The uniq won't reorder the output, so the second sort isn't needed. Also note that the standards don't clearly specify what happens when both the -f option and the -o option to ps are given (they place conflicting requirements on the output format; so specifying both is non-portable).
Putting your code in a loop to run your command line (and add a timestamp to the start of each line) is pretty easy. If you start the following script at 10am, by default it will produce reports at about 10:00, 10:15, 10:30, 10:45, 11:00, 11:15, 11:30, 11:45, and noon and then quit. If you pass arguments to the script you can change the number of minutes between samples and the number of samples to be run. It was a written and tested using a Korn shell, but will work with any shell that meets basic POSIX conforming shell requirements for arithmetic and variable expansions.
Code:
#!/bin/ksh
# Usage: counter [ repetition_count [ minutes_between_samples ]]
# Count and report number of processing running for each user.
reps=${1:-9} # # of samples to collect (default: 9 samples)
delay=${2:-15} # minutes between samples (default: 15 minutes)
printf "Gathering $reps samples $delay minutes apart\n"
while :
do DandT=$(date '+%m/%d/%y %H:%M')
printf 'Date Time User Num_Proc\n'
ps -A -o user|sort|uniq -c|while read count user
do [ "$user" = "USER" ] && continue
printf '%-20s %-20s %7d\n' "$DandT" "$user" "$count"
done
reps=$((reps - 1))
[ "$reps" -le 0 ] && break
echo
sleep $((delay * 60 - 2))
done
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if ; then
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Recorder number of process per user