Remove entire line from a file if 1st column matches a pattern


 
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# 1  
Old 06-11-2015
Remove entire line from a file if 1st column matches a pattern

I have one requirement to delete all lines from a file if it matches below scenario. File contains three column. Employee Number, Employee Name and Employee ID

Scenario is: delete all line if Employee Number (1st column) contains below
1. Non-numeric Employee Number
2. Employee Number that are over 99999 (data length is over 5 characters)
3. Employee Number that have any alpha characters

At present my file looks like as below

HTML Code:
0000-|John T|johnT
4906790742|amit kumar|akumar
SM36950SE2|Mike henry|mhenry1
03942|ronald F|ronaldf
36152|anshu ran|aran2
C0490|micheal z|michael3
I want my file should look like

HTML Code:
03942|ronald F|ronaldf
36152|anshu ran|aran2
I need your assistance and guidance on this.
# 2  
Old 06-11-2015
I suggest to read the man page of sed, especially the part about "one-address-commands".

I hope this helps.

bakunin
This User Gave Thanks to bakunin For This Post:
# 3  
Old 06-11-2015
Hello Anshu Rajan,

Kindly use code tags for commands/inputs/codes used in your posts in spite of HTML codes. Could you please try following and let me know if that helps.
Code:
awk -F"|" -vvar=5 '{if($1 !~ /[[:alpha:]]/ && $1 !~ /[[:punct:]]/ && length($1) <= var){print}}'  Input_file

Output will be as follows.
Code:
03942|ronald F|ronaldf
36152|anshu ran|aran2

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 4  
Old 06-11-2015
Thanks Ravinder, It worked exactly what I needed. Thanks a lot
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