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Wget in bash using sed and awk
05-01-2015
.#!/bin/bash
download () {
url=http://xxx.xx.xxx.xxx/data/getCSV.csv
echo -n " "
wget -O getCSV.txt --progress=dot $url 2>&1 | grep --line-buffered "%" | \
sed -u -e "s,\.,,g" | awk '{printf("\b\b\b\b%4s", $2)}'
echo -ne "\b\b\b\b"
echo " DONE"
menu
}
menu() {
while true
do
printf "\n Welcome to NGS menu (v1), please make a selection from the MENU \n
==================================\n\n
\t 1 Patient QC\n
==================================\n\n"
printf "\t Your choice: "; read menu_choice
case "$menu_choice" in
1) patient ;;
*) printf "\n Invalid choice."; sleep 2 ;;
esac
done
}
05-01-2015
.
05-01-2015
05-01-2015
..#!/bin/bash
cd 'C:\Users\cmccabe\Desktop\wget'
wget -O getCSV.txt http://xxx.xx.xxx.xxx/data/getCSV.csv --quiet
printf "downloading file, please wait"
echo "download complete, what is the id of the NGS patient: "; read id"
[ -z "$id" ] && printf "\n No ID supplied. Leaving match function." && sleep 2 && return
[ "$id" = "end" ] && printf "\n Leaving match function." && sleep 2 && return
input=$id
while read -r line
do
if [ -n "$id" ]; then
echo "match found in line $id"|sed 's/:.*//'
echo "$id"|sed 's/[^:]*://' >> match.txt
else
echo "no match found"
done|
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