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Using sed to delete one regular pattern with conditions

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# 1  
Old 04-09-2015
Wrench Using sed to delete one regular pattern with conditions
Hi All ,

I am having a file like this

INPUT FILE

###############################
Code:
addfd_mjlala kksks sksks ks 
annsns_bbox_2 (sksksk ksks )
adnndn_nsns_bbox_3 (( jsjsdj sjsj )
malm_dkdm lsls lsl
mdndk_mkmd_dkd_bbox_4_kdkd [jkssk jsjs[]
ksksk skksk_bbox_jsj_KSK ((jsjsj jsjsj )

#############################################

OUTPUT FILE

#########################################
Code:
addfd_mjlala kksks sksks ks 
annsns (sksksk ksks )
adnndn_nsns (( jsjsdj sjsj )
malm_dkdm lsls lsl
mdndk_mkmd_dkd  [jkssk jsjs[]
ksksk skksk ((jsjsj jsjsj )

##############################################

So you can see we have file with some instances having _bbox
I need a script which can delete the _bbox till the end of the word but retain the other word in the same line

I am using script like this

Code:
sed  's/_bbox.*$//g' INPUT_FILE > OUTPUT_FILE

But it is deleting the second word from each line having bbox

Thanks
Kshitij
# 2  
Old 04-09-2015
Code:
$ sed 's/_bbox[^ ]* / /' infile
addfd_mjlala kksks sksks ks
annsns (sksksk ksks )
adnndn_nsns (( jsjsdj sjsj )
malm_dkdm lsls lsl
mdndk_mkmd_dkd [jkssk jsjs[]
ksksk skksk ((jsjsj jsjsj )

Where [^ ] stands for "no blank" and * as many or none of these.
This User Gave Thanks to zaxxon For This Post:
kshitij
# 3  
Old 04-09-2015
If there can also be cases where there is no other word following your matched string and you want to remove that as well, you might want something more like:
Code:
sed -s 's/_bbox[^ ]* / /' -s 's/_bbox[^ ]*$//' infile

This User Gave Thanks to Don Cragun For This Post:
kshitij
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