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sed - remove begin of line up to the third and including occurence of character

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# 1  
Old 03-24-2015
sed - remove begin of line up to the third and including occurence of character
hello.
How to remove all characters in a line from first character ( a $ ) until and including the third occurrence of that character ( $ ).

Any help is welcome.
# 2  
Old 03-24-2015
With GNU sed:

Code:
$
$ chr="X"
$ str="one X two X three X four X five X six X over"
$
$ echo $str
one X two X three X four X five X six X over
$ echo $str | sed -r "s/$chr([^$chr]+$chr){2}//"
one  four X five X six X over
$
$ # =============
$
$ chr="$"
$ str="one $ two $ three $ four $ five $ six $ over"
$
$ echo $str
one $ two $ three $ four $ five $ six $ over
$ echo $str | sed -r "s/\\$chr([^\\$chr]+\\$chr){2}//"
one  four $ five $ six $ over
$
$

# 3  
Old 03-24-2015
If I understand your question correctly:
Code:
cat file | cut -d\$  -f4-

for example:
Code:
echo '$123$a..c$1234$this$isatest' |  cut -d\$  -f4- 

1234$this$isatest

# 4  
Old 03-25-2015
You could also try something like:
Code:
#!/bin/ksh
for delim in 'X' '$' ' ' '[' ']' '/'
do	printf "Using '%s' as delimiter...\n" "$delim"
	sed "s/[$delim][^$delim]*[$delim][^$delim]*[$delim]//" file
done

which should work with any sed and any delimiter character. (However, some versions of sed will fail with this if your delimiter is a multibyte character.)

With the input file file containing:
Code:
1 $ 2 $ 3 $ 4 $ 5 $ 6 $ 7
a X b X c X d X e X f X g
[A][B][C][D][E][F][G]
1/2/3/4/5/6/7

it produces the output:
Code:
Using 'X' as delimiter...
1 $ 2 $ 3 $ 4 $ 5 $ 6 $ 7
a  d X e X f X g
[A][B][C][D][E][F][G]
1/2/3/4/5/6/7
Using '$' as delimiter...
1  4 $ 5 $ 6 $ 7
a X b X c X d X e X f X g
[A][B][C][D][E][F][G]
1/2/3/4/5/6/7
Using ' ' as delimiter...
1$ 3 $ 4 $ 5 $ 6 $ 7
aX c X d X e X f X g
[A][B][C][D][E][F][G]
1/2/3/4/5/6/7
Using '[' as delimiter...
1 $ 2 $ 3 $ 4 $ 5 $ 6 $ 7
a X b X c X d X e X f X g
C][D][E][F][G]
1/2/3/4/5/6/7
Using ']' as delimiter...
1 $ 2 $ 3 $ 4 $ 5 $ 6 $ 7
a X b X c X d X e X f X g
[A[D][E][F][G]
1/2/3/4/5/6/7
Using '/' as delimiter...
1 $ 2 $ 3 $ 4 $ 5 $ 6 $ 7
a X b X c X d X e X f X g
[A][B][C][D][E][F][G]
14/5/6/7

# 5  
Old 03-25-2015
Maybe a multi-liner is better readable:
Code:
delim='$'
sed "
s/[$delim]//
s/[^$delim]*[$delim]//
s/[^$delim]*[$delim]//
" file

The following two are identical
Code:
cut -d\$ -f4- file

Code:
sed '
s/[^$]*[$]//
s/[^$]*[$]//
s/[^$]*[$]//
' file

# 6  
Old 03-25-2015
Quote:
Originally Posted by MadeInGermany
Maybe a multi-liner is better readable:
Code:
delim='$'
sed "
s/[$delim]//
s/[^$delim]*[$delim]//
s/[^$delim]*[$delim]//
" file

... ... ...
Easier to read? Maybe. Equivalent? No.
Code:
delim='$'
echo '1$2$3$4$5$6' | sed "s/[$delim][^$delim]*[$delim][^$delim]*[$delim]//"

echo '1$2$3$4$5$6' | sed "
s/[$delim]//
s/[^$delim]*[$delim]//
s/[^$delim]*[$delim]//
"

produces:
Code:
14$5$6
4$5$6

This User Gave Thanks to Don Cragun For This Post:
MadeInGermany
# 7  
Old 03-25-2015
I meant: the two following samples are identical with each other.
--
Now I see what you mean.
Last edited by MadeInGermany; 03-26-2015 at 05:38 PM..
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