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Java stack trace parser in awk

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# 1  
Old 03-18-2015
Java stack trace parser in awk
I want the developers to get a mail with Java stack traces on a daily bases. When something is flaged as known issue and will get a fix but mean while this does not need to get sent each dayl. This is what I got so far. It's a bash script that runs some AWK in it.

To get the files that needs to be parsed
Code:
WORK_LOG="$(find $APP_DATA/log/ -maxdepth 1 -newermt "1 days ago" ! -newermt "00:00")"

This is working. All stack traces contains "exception:" string and can be x lines untill a INFO log message accurs and we stop printing.
Code:
awk '/excepeion\:/{p=1;print;next} p&&/UTC Level INFO Scope/{p=0};p' $WORK_LOG  #>> output_test.log



Now what I need is to get rid of line containing known errors string so next part of awk don't catch them. I will give developers ability to paste strings that will be ignored into a config file
Code:
KNOW_EXCEPTION1="known error"

What I'm trying to do is get awk to remove the known exception rows before the print from here to here part.
Code:
awk '!/'"$KNOW_EXCEPTION1"'/{print $1} /excepeion\:/{p=1;print;next} p&&/UTC Level INFO Scope/{p=0};p'$WORK_LOG  >> output_test.log


This I found through google but I need to work it into what I already have and I can't get it to work.
Code:
awk '!/known error/'

Last edited by chipmunken; 03-18-2015 at 12:08 PM..
# 2  
Old 03-18-2015
Code:
awk -v exc="${KNOW_EXCEPTION1}" '$0 !~ exc ........

# 3  
Old 03-18-2015
How should I tie these together? I know a patter can follow another patter with a space but I'm getting syntax error if I do what you wrote.

Code:
awk -v exc="${KNOW_EXCEPTION1}" '$0 !~ exc  /excepeion\:/{p=1;print;next} p&&/UTC Level INFO Scope/{p=0};p' $WORK_LOG

Code:
awk: $0 !~ exc /excepeion\:/{p=1;print;next} p&&/UTC Level INFO Scope/{p=0};p
awk:                     ^ backslash not last character on line

# 4  
Old 03-18-2015
Code:
awk -v exc="${KNOW_EXCEPTION1}" '$0 !~ exc && /excepeion:/{p=1;print;next} p&&/UTC Level INFO Scope/{p=0};p' $WORK_LOG

Do you have 2 patterns that wou;d like to OR and do the action?
# 5  
Old 03-18-2015
Maybe sth along this line (untested):
Code:
awk     'NR==FNR                {KnErr[$0]; next}
         /exception/            {for (k in KnErr) if ($0 ~ k) next
                                 P=1
                                }
         /UTC Level INFO Scope/ {P=0}
         P
        ' known_errors.conf $WORK_LOG

# 6  
Old 03-18-2015
Quote:
Originally Posted by vgersh99
Code:
awk -v exc="${KNOW_EXCEPTION1}" '$0 !~ exc && /excepeion:/{p=1;print;next} p&&/UTC Level INFO Scope/{p=0};p' $WORK_LOG

Do you have 2 patterns that wou;d like to OR and do the action?
I want it to first remove the known exception rows before the next part works it's magic and prints the "wanted" exceptions

So first this
Code:
$0 !~ exc

and THEN do
Code:
/exception\:/{p=1;print;next} p&&/UTC Level INFO Scope/{p=0};p

# 7  
Old 03-18-2015
I guess what I had last should work. Try it and let us know.
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