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Variable in awk substituion

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# 1  
Old 03-16-2015
Variable in awk substituion
I have a file with 20 blank spaces.

I want to substitute each blank space for a string, and part of that string should include an incremental number [0 for first substitution, 19 for last]


Code

Code:
while read line3
do
                awk -v var=${line3} '{i=var; sub("^[[:blank:]]*$", "\\&\n@target G0.S"'$i'"\n@type xy"); print $0}' bla6 > bla7
                mv bla7 bla6
done<file3



Everything works except the incremental string value.

Help please!
# 2  
Old 03-16-2015
Not sure I understand what you're trying to achieve. Please show the input files and the desired output.
For certain the (single) quotation around the $i can't work.
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