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Awk: is it possible to print into multiple columns?

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Top Forums Shell Programming and Scripting Awk: is it possible to print into multiple columns?
# 1  
Old 03-05-2015
Awk: is it possible to print into multiple columns?
Hi guys,

I have hundreds file like this, here I only show two of them:
file 1
Code:
feco4_s_BB95.log                                    ZE_1=-1717.5206260
feco4_t_BB95.log                                    ZE_1=-1717.5169250
feco5_s_BB95.log                                    ZE_1=-1830.9322060

file 2
Code:
feco4_s_BBRC.log                                    ZE_1=-1717.2394670
feco4_t_BBRC.log                                    ZE_1=-1717.2382150
feco5_s_BBRC.log                                    ZE_1=-1830.6170990

can I get an output like this? which is simple for copying into excel.
Code:
feco4_s_BB95.log        -1717.5206260 -1717.2394670
feco4_t_BB95.log        -1717.5169250 -1717.2382150
feco5_s_BB95.log        -1830.9322060 -1830.6170990

Thank you very much for your kind help!

Zhen
# 2  
Old 03-05-2015
The order of results is not guaranteed:

Code:
{ sub(/ZE_1=/,""); A[$1]=A[$1]" "$2 } END { for(X in A) print X, substr(A[X],1) }' inputfile

# 3  
Old 03-05-2015
Quote:
Originally Posted by Corona688
The order of results is not guaranteed:

Code:
{ sub(/ZE_1=/,""); A[$1]=A[$1]" "$2 } END { for(X in A) print X, substr(A[X],1) }' inputfile

Thanks. But the order should consistent with the file name, let say the second column should be the numbers from the file2, and so the hundredth column should be from the file100. ortherwise, these numbers are not in order and are becoming meaningless.

could it possibly be processed with cycles?
# 4  
Old 03-05-2015
Are your first column always the same and in same order?
If yes, this might help extract col2 from all your files , but you need to paste col1 from one of your files.

Should maintain order.


Code:
BEGIN {
  count = 1
}

FNR == 1 && FNR < NR {
  count++
}

{
  if ( _[FNR] ) {
    while ( c[FNR] != count-1 ) {
      _[FNR] = (_[FNR] " " sprintf("%8s",""))
      c[FNR]++
    }
    _[FNR] = (_[FNR] " " sprintf("%-8s",$2))
    c[FNR]++
  }
  else if ( count == 1 ) {
    _[FNR] = sprintf("%-8s",$2)
    c[FNR]++
  }
  else {
    while ( c[FNR] != count-1 ) {
      if ( _[FNR] )
        _[FNR] = (_[FNR] " " sprintf("%8s",""))
      else
        _[FNR] = sprintf("%8s","")
      c[FNR]++
    }
    _[FNR] = (_[FNR] " " sprintf("%-8s",$2))
    c[FNR]++
  }
}

END {
  for (i=1; i<=length(_); i++)
    print _[i]
}


Save this as liuzhencc.awk , give a execute status like chmod 777

and run as

Code:
awk -f liuzhencc.awk file1 file2 .... filen

# 5  
Old 03-05-2015
Quote:
Originally Posted by liuzhencc
Thanks. But the order should consistent with the file name, let say the second column should be the numbers from the file2, and so the hundredth column should be from the file100. ortherwise, these numbers are not in order and are becoming meaningless.

could it possibly be processed with cycles?
Are they sorted, and guaranteed not missing any rows? You could just use paste.
# 6  
Old 03-05-2015
I think it works with the following code, but in very an inefficient way.
Code:
/*add the file name to the first row*/
for i in file*; do
printf "%20s" ${i} >> $i.txt;
done

printf "\n" >> ../$i.txt;

/*print the numbers of the second row from each file $i*/
for ((j=1;j<=11;j++)); do
for i in file*; do
Num=$(awk "NR==${j}" ${i} | awk -F= '{print $2}');
printf "%20.7f" "${Num}" >> $i.txt;
done;

printf "\n" >> $i.txt;

done;

# 7  
Old 03-05-2015
Are they sorted, and guaranteed not missing any rows? You could just use paste.
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