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Include pathname in awk output?

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# 1  
Old 02-25-2015
Include pathname in awk output?
I am running an awk to verify all the memory settings for tomcat, and need to include path or directory in output ....

I am running:
Code:
awk '{ print $3 }' /opt/dir1/dir2/*/tomcat/bin/setenv.sh

Output results:
Code:
-Xms1024m
-Xmx1536m
-Xmx1536m
-Xmx1024m
-Xms1024m
-Xms1024m
-Xms512m
-Xms1024m
-Xms1536m
-Xms512m
-Xmx1024m
-Xmx1024m
-Xmx1024m

Is there something I can include in my command that would include the specific directory for '*' in the output?

Like so:
Code:
-Xmx1024m /dir3

Where dir3 would be * in /opt/dir1/dir2/*/tomcat/bin/setenv.sh

Or am I going about this completely wrong? :/
Last edited by Scrutinizer; 02-25-2015 at 01:09 PM.. Reason: code tags
# 2  
Old 02-25-2015
FILENAME would be /opt/dir1/dir2/whatever/tomcat/bin/setenv.sh.

Code:
awk '{ X=FILENAME;  sub(/\/opt\/dir1\/dir2\//, "", X); sub(/\/tomcat\/bin\/setenv[.]sh/, "", X);  print X, $3 }' /opt/dir1/dir2/*/tomcat/bin/setenv.sh

This User Gave Thanks to Corona688 For This Post:
kgolli
# 3  
Old 02-25-2015
Please use code tags as required by forum rules!

man awk:
Quote:
7. Builtin-variables
The following variables are built-in and initialized before program execution.
.
.
.
FILENAME name of the current input file.
Code:
awk '{print FILENAME}' /opt/dir1/dir2/*/tomcat/bin/setenv.sh

You can't find out the position of "*" in your input string as it will be expanded by the shell long before awk gets hands on it.
# 4  
Old 02-25-2015
Thank you Corona688! Your solution worked for me!
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