awk to bash variable suddenly stores filessystem data
Dear Members,
I have the following situation I do not understand:
I have a large json encoded file which I need to grep and afterwards want to extract specific information.
I use this command to to that:
I was able to cut the problem to a minimal example:
Let's have a file /tmp/file with
Code:
"* My Information"
Now,
Code:
cat /tmp/file | awk -F '"' '{print $2}'
gives the expected result:
Code:
* My Information
Yet,
Code:
content=`cat /tmp/file | awk -F '"' '{print $2}'`
gives
Code:
file1 file2 My Information
The problem is the asterisk (*). If the asterisk is not present, it does not get substituted with the files and directories.
I assume I have to escape those characters but I cannot find a table of characters which have to be escaped. Maybe there is another way using other quote types or something else.
Any further help is very much appreciated!
I suspect it's just the way you're displaying $content.
echo * will be globbed by the shell before it display anything (which results in the list of filenames). Double-quotes should fix it (i.e. echo "${var}").
hi,
would you help me?
i have file total.csv
"a","e23","f"
"b,"34d","g"
"c","45f","f"
"d","45s","f"
count.csv
3
i do this :
paste -d',",' total.csv count.csv
but the result like this:
"a,"e23","f" 3
"b,"34d","g" (1 Reply)
hi all,
i need the shell script for he below requirement
i had the input file as
a_20121217_035120( frmat is a_date_hhmmss)
a_20121217_035128
a_20121217_035456
a_20121217_035767
a_20121217_035178
a_20121217_035189
a_20121217_035220
my output should be
a_20121217_035456... (0 Replies)
Hi All,
I tried below code
getting error.
AD=0
ZERO=0
if then
echo "AD is zero select another symbol"
fi
syntax error near unexpected token `fi'
plz help me to solve this error (4 Replies)
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Here is the code I have:
#! /bin/sh
for I in `ps -eaf h | awk '{print $1}'... (7 Replies)
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I am new to UNIX.
I got the file from Oracle, with
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something like... (1 Reply)