Shell Programming and Scripting

 names1="cdb1 cdb2 cdb3"
 names2="pdb1 pdb2 pdb3"
 for names in $names1
 do
   export $DB=$name
   export $PDB=pdb1 ------------How to achieve this?

names1="cdb1 cdb2 cdb3"
names2="pdb1 pdb2 pdb3"

set $names2
for name in $names1; do
   export DB=$name
   export PDB=$1
   shift
   echo "$DB:$PDB"
done

names1=(cdb1 cdb2 cdb3)
names2=(pdb1 pdb2 pdb3)

for ((i=0; i<${#names1[@]}; i++)) 
do
   export DB=${names1[i]}
   export PDB=${names2[i]}
   printf "%s\n" "$DB:$PDB"
done

 declare -a names1=(cdb1 cdb2 cdb3)
declare -a names2=(pdb1 pdb2 pdb3)
  
 `(' unexpected

set -A names1 cdb1 cdb2 cdb3
set -A names2 pdb1 pdb2 pdb3

for((i=0; i<${#names[@]}; i++));do

unexpected (

 for((i=0; i<${#INSTNAMES[@]}; i++))
 do

 unexpected (

 for (i=0; i<${#INSTNAMES[@]}; i++)
 do

for  ((i=0; i<${#INSTNAMES[@]}; i++))

( unexpected

set -A names1 cdb1 cdb2 cdb3
set -A names2 pdb1 pdb2 pdb3

i=0
while [[ $i -lt ${#names1[@]} ]]
do
   export DB=${names1[i]}
   export PDB=${names2[i]}
   printf "%s\n" "$DB:$PDB"
   i=$((i+1))
done