Convert a date stored in a variable to epoch date


 
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Old 02-18-2015
It was my mistake, I changed the code to

Code:
 
epoch_from_date="`/progs/bin/date +%s -d "$from_date"`"
epoch_to_date=\"`/progs/bin/date +%s -d "$to_date"`\"

and its working fine. Thanks for resolving the issue.
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GETDATE(1)							   User Commands							GETDATE(1)

NAME
getdate - AME SYNOPSIS
[-dv][-n dec][-f format] [ra dec sys] itype2otype [date and/or time] DESCRIPTION
Convert date and time between various formats [-dv][-n dec][-f format] itype2otype @file itype: nfd=ISOFITS fd=FITS, dt=yyyy.mmdd, hr=hh:mm:ss, deg=dd:mm:ss jd=Julian Date, mjd=Modified Julian Date hjd=Heliocentric Julian Date, mhjd=Modified HJD ep=epoch, epj=Julian epoch, epb=Besselian epoch lt=local time, ut=UT, ts=seconds since 1950-01-01 now=current time, ang=fractional degrees otype: fd=FITS, dt=yyyy.mmdd, jd=Julian Date, mjd=Modified Julian Date hjd=Heliocentric Julian Date, mhjd=Modified HJD hr=hh:mm:ss, deg=dd:mm:ss, ang=fractional degrees ep=epoch, epj=Julian epoch, epb=Besselian epoch ts=seconds since 1950-01-01, tsu=Unix sec, tsi=IRAF sec gst=Greenwich Sidereal Time, lst=Local Sidereal Time @file: First one or two columns are in itype format ra dec sys: Need for Heliocentric conversions -a: Append date to input file, if there is one -d: Print date without time -e: Print output as ET/TDT/TT converting from UT -f: Format for output number (C printf) -h hours: Longitude in hours, west positive -l degrees: Longitude in degrees, west positive -n: Number of decimal places in sec, epoch, JD -t: Print time without date -v: Verbose getdate 3.8.4 June 2012 GETDATE(1)