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Top Forums Shell Programming and Scripting Anyone like a challenge?
# 8  
Old 02-11-2015
Quote:
Originally Posted by BatterBits
Hi Don,

Thanks - but that doesn't work - the output is "unsorted", still contains the timestamp which I don't need.

Code:
h20150204.log.001 05:10:30 completed successfully
h20150207.log.001 05:50:30 JOBFAILURE: COMPLETED WITH ERRORS RC=201
h20150210.log.001 00:57:23 JOBFAILURE: COMPLETED WITH ERRORS RC=201
h20150211.log.003 00:35:39 OTHER MESSAGE
h20150127.log.001 02:32:00 completed successfully

-----
Regards,


Ian
That is strange. By default, the output from ls is sorted by filename and (as long as the character(s) in your log file names before the date stamp is(are) constant) the output should be in sorted order. And, tail won't rearrange the output order, and the for loop won't rearrange the output order. Are there hidden characters in your filenames? Did you pass options to ls that I didn't use? Is there a filename ending with .log. followed by three digits that has a minus sign as its first character?

I didn't see your additional requirement to strip out the timestamp until after I submitted my response. You already have suggestions on how to deal with that (as long as the last lines of your log files don't contain adjacent sequences of multiple spaces and tabs that you don't mind being converted to single spaces).
This User Gave Thanks to Don Cragun For This Post:
Neo
# 9  
Old 02-11-2015
Don,

Don't want to take too much of your time - given that I have a result - however, to answer your points:

I copied & executed your code exactly from your reply - and pasted the output. As far as I know, there are no hidden characters, no minus signs and nothing added.

Interestingly, if I execute the bracketed ls statement, I get this:

Code:
>ls *.log.0??|tail -n 6
h20150126.log.001   h20150129.log.001   h20150201.log.001   h20150204.log.001   h20150207.log.001   h20150210.log.001   h20150211.log.003
h20150127.log.001   h20150130.log.001   h20150202.log.001   h20150205.log.001   h20150208.log.001   h20150211.log.001   h20150212.log.001
h20150128.log.001   h20150131.log.001   h20150203.log.001   h20150206.log.001   h20150209.log.001   h20150211.log.002   h20150212.log.002

this lists them top to bottom, left to right
###
looking at the output from the whole command, it is presenting the files in left to right top to bottom from the above output - if you know what I mean - ie the top row of the output above is represented as the start of the output below....

Code:
 > for lf in $(ls *.log.0??|tail -n 6);do printf '%s ' "$lf";tail -n 1 "$lf";done
h20150126.log.001 23:52:02 completed successfully
h20150129.log.001 20:58:34 completed successfully
h20150201.log.001 23:01:47 completed successfully
h20150204.log.001 05:10:30 completed successfully
h20150207.log.001 05:50:30 JOBFAILURE: COMPLETED WITH ERRORS RC=201
h20150210.log.001 00:57:23 JOBFAILURE: COMPLETED WITH ERRORS RC=201

Don't know why that would be. I tried adding "-l" to the bracketed command - to list one file per line, but that failed spectacularly!

----
Regards,


Ian
This User Gave Thanks to BatterBits For This Post:
Neo
# 10  
Old 02-11-2015
What OS are you using?

When ls output is directed into a pipe (or, for that matter, anything that is not directed to a terminal), the standards require it to produce one filename per output line; nothing at all like what you showed in your last post!
# 11  
Old 02-11-2015
On the machine from which the output has been taken:

Code:
 > uname -srv
HP-UX B.11.23 U

I'm not making it up - the results are absolutely copied & pasted from the live server I happen to be working on at the moment - I'll try it elsewhere when I have the opportunity.
---
Regards,


Ian

---------- Post updated at 02:48 AM ---------- Previous update was at 02:42 AM ----------

Here's another:

Code:
<hostname removed>> ls *.log.0??|tail -n 6
usage: tail [+/-[n][lbc][f]] [file]
       tail [+/-[n][l][r|f]] [file]
<hostname removed> > ls *.log.0??|tail -6
h20150127.log.001   h20150131.log.001   h20150204.log.001   h20150208.log.001
h20150128.log.001   h20150201.log.001   h20150205.log.001   h20150209.log.001
h20150129.log.001   h20150202.log.001   h20150206.log.001   h20150210.log.001
h20150130.log.001   h20150203.log.001   h20150207.log.001   h20150211.log.001
<hostname removed> > uname -srv
SunOS 5.9 Generic_118558-28
<hostname removed> >

---------- Post updated at 02:50 AM ---------- Previous update was at 02:48 AM ----------

Same thing:

Code:
<hostname removed> > for lf in $(ls *.log.0??|tail -6 );do printf '%s ' "$lf";tail -1 "$lf";done
h20150127.log.001 04:26:27 completed successfully
h20150131.log.001 04:33:33 completed successfully
h20150204.log.001 04:31:47 completed successfully
h20150208.log.001 07:46:14 completed successfully

Last edited by rbatte1; 02-12-2015 at 06:28 AM.. Reason: Added CODE tags for output
# 12  
Old 02-11-2015
The output you are showing would be what one would expect if you had an alias installed for ls that was defined by:
Code:
alias ls='ls -C'

What do the commands:
Code:
type ls;alias ls

print for you?
This User Gave Thanks to Don Cragun For This Post:
Neo
# 13  
Old 02-11-2015
Here is the output (almost identical) from the 2 boxes:


Code:
> type ls;alias ls
ls is an alias for ls -FC
ls=ls -FC

and

Code:
 > type ls;alias ls
ls is an alias for ls -FC
ls='ls -FC'

I guess that's standard throughout the "estate" then.
----
Regards



Ian
# 14  
Old 02-12-2015
So could you try using \ls instead of ls?


(or put Don's suggestion into a script and run it like that instead of from the command line)
Last edited by Scrutinizer; 02-12-2015 at 12:27 AM..
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