I have searched through google, and this forum to try and find the answer, but alas, nothing quite hits the whole answer.
I am trying to read the last line (or lines) of some log files. I do this often.
The files are named sequentially, using the date as part of the file name, and appending the iteration so like this:
And I want generally to tail -1 each of the files to see the end result
There may be 33 files - or may be 3000 files - different each time - I don't want to have to manually specify the filenames - but "*log.0??" works for a "filter". Aged files are compressed (.Z) or gzipped (.gz), and obviously I don't want to read these files.
However.
All of the methods I have tried , using find - don't sort the files into the correct order - I need it to be in chronological order, and I also need to see the filename - preferably on the same line as the resultant output - which is effectively succeeded or failure.
All the attempts I have made using ls -ltr error:
Just to make this a little more challenging - this will be across multiple different O/Ss, including HP-UX, SunOS, RHEL and more.
I would prefer a solution which doesn't need to create a script file - but any amount of typing (or pasting) at the command prompt is acceptable.
The result I'm looking to achieve is rather like:
So far, the closest I have to what I need is:
But this fails because it isn't sorted in the correct way, and it concatenates the filename and timestamp (with no gap) like so:
If anyone has any fabulous ideas or can point me in the right direction, I'd be most grateful...
Background:
For anyone who's interested, I'm a DBA currently working in 2nd line support - looking after about 8000 database instances over 3500 hosts. This particular query is to look at backup log files, and try & determine where it all went wrong....
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Regards,
Try:
Note: Using *.log.0?? would limit the result to the first 99 iterations for any particular day. Perhaps a better alternative would be to use: *.log.[0-9][0-9][0-9]
Last edited by Scrutinizer; 02-11-2015 at 08:41 PM..
These 2 Users Gave Thanks to Scrutinizer For This Post:
Given that the filenames contain the date and a sequence number within that date, I don't see the need for sorting by time in ls, and unless there are files in multiple directories, there is no need for find. Doesn't this do what you need?:
Thanks - but that doesn't work - the output is "unsorted", still contains the timestamp which I don't need.
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Regards,
Ian
---------- Post updated at 01:07 AM ---------- Previous update was at 12:59 AM ----------
Quote:
Originally Posted by Scrutinizer
Try:
Note: Using *.log.0?? would limit the result to the first 99 iterations for any particular day. Perhaps a better alternative would be to use: *.log.[0-9][0-9][0-9]
Yes, I get that, thanks. Generally, there won't be more than 99 files - but I know how to deal with it if there are - the syntax I used, because some of the files are compressed, so I couldn't use *log.*
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