Shell Programming and Scripting

Using a bash for loop to pass variables into a nawk loop to capture a string in an sftp log. Tried several different syntax methods to have the variable treated as a regex so the loop will capture the string.

Code:

for i in `cat /tmp/dar3.out.2`
do
nawk -vst=$i '$5 ~ /$st/ && /closed/ && /user/ && !/ORG/  && !/LE/ { for (x=1;x<=NF;x++) if ($x~"user") print $(x+1) } /var/adm/sftplog >> /tmp/dar3.out.cli
done

The contents of /tmp/dar3.out.2 are all sftp session log ID's.

15103
27888
23641
3161
15355
23040
26631
1065
7220
12443
8505
29111
29114
27654
11999
22904
19679

Please advise if there is a way to have

Code:

 /$st/

treated as a regex so I can pass into nawk loop.

Thanks

Must be $5 ~ st

If I try using that I receive the following -

Code:

+ nawk -vst=19679 '$5 ~ st && /closed/ && /user/ && !/ORG/  && !/LE/ { for (x=1;x<=NF;x++) if ($x~"user") print $(x+1) } ' /var/adm/sftplog
nawk: empty regular expression
 input record number 1, file /var/adm/sftplog
 source line number 1

Try -v st=12345