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Seeing unexpected results when i run through cronjob

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# 1  
Old 02-04-2015
Seeing unexpected results when i run through cronjob
Hi

I'm having hard time here with below script. If i run script manually i see expected results but, if i keep this script in cron job i'm getting unexpected results. Unexpected results means even though condition is true,cronjob returning output of else condition.

This script and cronjob running on same linux server.Please let me know if i need to make any changes in code.



Code:
#!/bin/bash
#set -x
content1='bind successful'
file1=/cpt/app/scripts/test/sra
 
echo "testing" >>$file1 &
 
hn=ldrfvb1232.example.com
port=2507
user=dummy
pwd=xxxxxx
 
wallet_pwd=xxxxxx
 
amm=$(/cpt/apps/oracle/Oracle_Home/bin/ldapbind -h $hn -p $port -D "cn=$user" -w $pwd -U 2 -W "file:/cpt/apps/scripts/test/wallet" -P $wallet_pwd)
 
 
 
if [ "$amm" = 'bind successful' ]; then
 
echo  "$hn:$port-Health Check SUCCESS!" >>$file1 &
else
echo "$hn:$port-Health NOT-OK!" >>$file1 &
fi
exit

---------- Post updated at 08:01 PM ---------- Previous update was at 07:43 PM ----------

Can Anyone help on this?
# 2  
Old 02-04-2015
The first suspect is an environment variable. Take just the first lines of your script - put 'em in another file. add:

Code:
set >/myhome/dir/set.output

create a cronjob in the crontab. Let it run once. Remove the entry from the crontab - or comment it out at least. set.output MUST match the output of

set > t.txt

from your command line. try doing a diff. You can ignore RANDOM and some other junk.

From that point on you know what to do. Make your cronjob have the right stuff.
# 3  
Old 02-05-2015
Sharing jim mcnamara's first suspicion I can't see that script relying on a variable anywhere. All paths are absolute, all variables are defined locally... What do you get if you uncomment the set -x? What's the contents of $amm?

And, why do you echo from the background?
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