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I want to grep the text value in UNIX shell file

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Top Forums Shell Programming and Scripting I want to grep the text value in UNIX shell file
# 8  
Old 02-02-2015
Hello lakshmanraok,

Following may help you in same.
Code:
echo -H\"asdfgsdfgsdfgg5345dg4545\" | awk '{match($0,/H\".*\"/);print substr($0,RSTART,RLENGTH)}'
OR
awk '{match($0,/H\".*\"/);A=substr($0,RSTART,RLENGTH);if(A){print A}}'  Input_file

Output will be as follows.
Code:
H"asdfgsdfgsdfgg5345dg4545"


Thanks,
R. Singh
Last edited by RavinderSingh13; 02-02-2015 at 06:55 AM.. Reason: Added one more solution on same
# 9  
Old 02-02-2015
Can you please explain this command, how it works?

---------- Post updated at 06:42 AM ---------- Previous update was at 06:03 AM ----------

If I am giving this command
Code:
awk '{match($0,/-G\".*\"/);A=substr($0,RSTART,RLENGTH);if(A){print A}}' file name

I am getting value below while runing above command

Code:
-G"sdfsdg4353246dfgsdf5464" - fsdf -dsfsd -sdfsdf

Please suggest me on this.

I need only value that is with double quotes after -G
# 10  
Old 02-02-2015
Hello lakshmanraok,

Following may help you in same.
Code:
awk '{match($0,/H\".*\"/);A=substr($0,RSTART+2,RLENGTH-3);if(A){print A}}'  Input_file

Here I am matching regex match($0,/H\".*\"/) and keywords RSTART, RKENGTH will be set according to matching of regex so I am taking it's values to a variable named A and if A is NOT empty then print it. Hope this helps, you can also read man awk for more information on same.

Thanks,
R. Singh
# 11  
Old 02-02-2015
Hi Guys,

I am getting the below complete value,

Code:
a45ddfg_654dfg_fgf65_hghjhj42334" 
-t1 -t23 -tyutyu -hgjghj   -ertert -ghfgh -dfgdf -dfgdfg -ghjhj

while executing the below command:

Code:
awk '{match($0,/\-G\".*\"/);A=substr($0,RSTART+4,RLENGTH-2);if(A){print A}}' file name


the actual line in my shell script is:

Code:
/bnbn/er/hhhh12/gggg/bin/fg_fghfghfgh  
"/bnbn/hg/vbn12/xccvb/log/fgfgh_1/" 
-w "dfgd:dfgdfg:dfgdfg" 
" -ghjghjgh 
-E\"hgjghj.txt\"  
-G"a45ddfg_654dfg_fgf65_hghjhj42334" 
-t1 -t23 -tyutyu -hgjghj   -ertert -ghfgh -dfgdf -dfgdfg -ghjhj
"


but I want only the highlighted value.




thanks in advance!

Regards,
Lakshman
# 12  
Old 02-02-2015
Hello Lakshman,

I am not sure you tried my solutions in privious posts or not, following is working for me.
Code:
awk '{match($0,/G\".*\"/);A=substr($0,RSTART+2,RLENGTH-3);if(A){print A}}'  Input_file

Output is as follows.
Code:
a45ddfg_654dfg_fgf65_hghjhj42334

Thanks,
R. Singh
# 13  
Old 02-02-2015
No ...I am not getting using this command , because still i am getting some more text after the value:

Code:
a45ddfg_654dfg_fgf65_hghjhj42334 -dfgdsfg -0dfgdf -gdfg

like this, why because my code value with in another two double quotes like

Code:
" -G " sddfdfgfgdfgfg" "

below is the sample code

Code:
" -ghjghjgh 
-E\"hgjghj.txt\"  
-G"a45ddfg_654dfg_fgf65_hghjhj42334" 
-t1 -t23 -tyutyu -hgjghj   -ertert -ghfgh -dfgdf -dfgdfg -ghjhj
"

I dont know why its not showing ending with " at code value after G?

Can you suggest me on this?

Thanks in advance!
Last edited by lakshmanraok; 02-02-2015 at 09:24 AM..
# 14  
Old 02-02-2015
Code:
awk -F\" 'sub(/^.*-H *"/,"") && sub(/".*$/,"")' file
asdfgsdfgsdfgg5345dg4545

---------- Post updated at 14:54 ---------- Previous update was at 14:50 ----------

Exchange the H in above with G to get a45ddfg_654dfg_fgf65_hghjhj42334
 from your sample.
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