Shell Programming and Scripting

Code:

sed /'1-2'/&^/ filename

suppose there is a file containing three lines , how do we do delete the word from each line?

Code:

hyter efr frf
 rerfer efe ewd
 cdcf evrfgf erfv

the output has to look like

Code:

frf
ewd
erfv

Try:

Code:

sed 's/.* //' file

--
or awk

Code:

awk '{print $NF}' file

Code:

sed 's/^ *[^ ][^ ]*  *//'

Remove optional leading spaces, the first non-space character and any immediately following non-space characters, a space and any immediately following spaces. Now, that's the first word, as the title requested. The example contradicts that, and says keep the last word:

Code:

sed 's/.* \([^ ][^ ]*\) */\1/'

Which allows for and removes trailing spaces on the line. Remove everything up to a space that is followed by a non-space, preserve the non-space and any immediately following non-space characters, but discard any trailing spaces on the line.