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Php assign selection to a variable

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# 1  
Old 01-18-2015
Php assign selection to a variable
can someone help me assign the selection of a drop down menu to a variable? the variable i need to store the selection in is inputA.

Code:
<form name="inputA">
<p align="center">
<p align="center">Name: <input name="inputA" type="text" size="45">
<select>
<?php
if ($handle = opendir('/var/tmp')) {
    while (false !== ($entry = readdir($handle))) {
        if ($entry != "." && $entry != "..") {
            $list[] = $entry;
        }
    }
    closedir($handle);
}
natcasesort($list);
sort($list);
foreach($list as $file) {
        echo "<option value='$file'>$file</option> \n";
        #echo "<input name="inputA" type="text" size="45">";
        $scanoption = '$file';

}
?>
</select>

can anyone help with this?
Last edited by SkySmart; 01-18-2015 at 04:31 PM..
# 2  
Old 01-19-2015
If you give your select a name then when the user submits the form the selected value will be in the _POST array.

e.g. something like:
Code:
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
   $inputA=$_POST['dir_name']
}
else { /* REQUEST */
?>
<form name="inputA">
 <p align="center">
  <select name="dir_name">
etc...

This User Gave Thanks to CarloM For This Post:
SkySmart
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