below file is job list, the records without s( in the begining is job name in the box, the records with s() is the job depends on them (some of them in the box, some of them not in the box). I need to use script to find the job name not in the box.
from above file, the inbox job is and the job not inbox is
I wrote a script to do this but it is a little bit compleated. I am wonder if there is any easy way to achive this task.
my script as below.
grep ^s( filename > file1
grep -v ^s > file2
then remove s( and ) with command sed 's/s(//' |sed 's/)//'
then compare these two file2 and file1 find outbox job.
Following may help you in same.
It will create 2 files named Found_jobs and NOT_found_jobs as follows.
Thanks,
R. Singh
Thanks Singh for your reply.
the ways you provied work fine.
my goal is to compare the found and not found job and list the jobs that is in found but not in not_found. in above case I want to get below out put
is it possible to achieve this within same command?
the ways you provied work fine.
my goal is to compare the found and not found job and list the jobs that is in found but not in not_found. in above case I want to get below out put
is it possible to achieve this within same command?
thanks in advance
Hello Ken6503,
Following may help you in same. Output will be as follows. EDIT: Adding non oneliner command for same.
Thanks,
R. Singh
Last edited by RavinderSingh13; 01-09-2015 at 11:41 AM..
Reason: Added non one liner form of code
This User Gave Thanks to RavinderSingh13 For This Post:
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