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# 1  
Old 12-23-2014
Linux Renaming file in batch
Hi guys,

I need a script to change the file names e.g.:-

below are the mentioned files, i want t0 change the last character of the name 00000.cdr with e.g bep01.smsc.191214210500-00000.cdr to bep01.smsc.191214210500-92311.cdr next file be like bep01.smsc.191214210500-92312.cdr

Code:
[root@bep01 done]# ls -ltr | grep 00000.cdr

-rw-r--r--  1 ss7 ss7  58286 Dec 19 21:09 bep01.smsc.191214210500-00000.cdr
-rw-r--r--  1 ss7 ss7  52022 Dec 19 21:14 bep01.smsc.191214211000-00000.cdr
-rw-r--r--  1 ss7 ss7  58772 Dec 19 21:19 bep01.smsc.191214211500-00000.cdr
-rw-r--r--  1 ss7 ss7  51905 Dec 19 21:24 bep01.smsc.191214212000-00000.cdr
-rw-r--r--  1 ss7 ss7  52414 Dec 19 21:29 bep01.smsc.191214212500-00000.cdr
-rw-r--r--  1 ss7 ss7  49413 Dec 19 21:34 bep01.smsc.191214213000-00000.cdr
-rw-r--r--  1 ss7 ss7  54275 Dec 19 21:39 bep01.smsc.191214213500-00000.cdr
-rw-r--r--  1 ss7 ss7  46818 Dec 19 21:44 bep01.smsc.191214214000-00000.cdr
-rw-r--r--  1 ss7 ss7  53009 Dec 19 21:49 bep01.smsc.191214214500-00000.cdr
-rw-r--r--  1 ss7 ss7  49944 Dec 19 21:54 bep01.smsc.191214215000-00000.cdr
-rw-r--r--  1 ss7 ss7  51558 Dec 19 21:59 bep01.smsc.191214215500-00000.cdr
-rw-r--r--  1 ss7 ss7  50739 Dec 19 22:04 bep01.smsc.191214220000-00000.cdr
-rw-r--r--  1 ss7 ss7  47979 Dec 19 22:09 bep01.smsc.191214220500-00000.cdr

I have 500 files please help to change the name like above.
Moderator's Comments:
Mod Comment Putting QUOTE tags around your entire post and removing ICODE tags does not help us see the commands you have used, the output those commands produced, nor the input you're trying to process. Please use CODE tags when showing nulti-line code segments, sample input, and sample output. You can use ICODE tags when showing in-line input, output, or code in the middle of a sentence.
Last edited by Don Cragun; 12-24-2014 at 02:15 AM.. Reason: Removed QUOTE tags, added CODE and ICODE tags.
# 2  
Old 12-23-2014
Quote:
Originally Posted by mfaizan40
hi guys,

i need a script to change the file names e.g

abc.122314175400-00000.txt to abc.122314175400-00001.txt

abc.122314175400-00000.txt to abc.122314175400-00002.txt

abc.122314175400-00000.txt to abc.122314175400-00003.txt

i have 500 files please help to chnge the name like above.
Hello mfaizan40,

Welcome to forums, could you please use code tags for commands/codes which you are using in your posts as per forum rules.
Following link may help you in same for understanding rules for forum.

https://www.unix.com/misc.php?do=cfrules


Regarding your query, I can see all files which you want to rename are of same name(provided by you in question), is it a typo?
Could you please provide more details on same it will be helpful for us to help you in same.


Thanks,
R. Singh
# 3  
Old 12-23-2014
Code:
$ cat file
abc.122314175401-00000.txt
abc.122314175400-00000.txt
abc.122314175402-00000.txt
$ sort file | awk ' { flnm=$0;sub("00000",sprintf("%05d",NR)); print "mv " flnm " " $0 } '
mv abc.122314175400-00000.txt abc.122314175400-00001.txt
mv abc.122314175401-00000.txt abc.122314175401-00002.txt
mv abc.122314175402-00000.txt abc.122314175402-00003.txt

Code:
sort file | awk ' { flnm=$0;sub("00000",sprintf("%05d",NR)); print "mv " flnm " " $0 } ' | sh

# 4  
Old 12-24-2014
thanks for your reply. i edit the post with the exact scenario. can you please check and help me.

---------- Post updated at 01:08 AM ---------- Previous update was at 01:01 AM ----------

i edit the post with the exact scenario.can you plz check.
# 5  
Old 12-24-2014
You can use anbu23's suggestion as a starting point, with some minor changes since the names you want aren't stored in a file and since you don't want the numbers in the new names to start at 00001. If the command ls *-00000.cdr works without giving you an error for an argument list that is too long, try something like:
Code:
startseq=92311
ls *-00000.cdr | awk -v s="$startseq" '{f=$0;sub("00000.cdr",sprintf("%05d.cdr",s++)); print "mv", f, $0}' | sh

otherwise, try something like:
Code:
startseq=92311
ls | grep -F '-00000.cdr' | awk -v s="$startseq" '{f=$0;sub("00000.cdr",sprintf("%05d.cdr",s++)); print "mv", f, $0}' | sh

Last edited by Don Cragun; 12-24-2014 at 04:01 AM.. Reason: Changed ".txt" to ".cdr" to match name changes in post #1 in this thread.
This User Gave Thanks to Don Cragun For This Post:
wolf3d
# 6  
Old 12-24-2014
Quote:
Originally Posted by mfaizan40
thanks for your reply. i edit the post with the exact scenario. can you please check and help me.

---------- Post updated at 01:08 AM ---------- Previous update was at 01:01 AM ----------

i edit the post with the exact scenario.can you plz check.
Hello mfaizan40,

Kindly use code tags for commands and codes which you are using your posts as per forum rules. Following may help you in same.
I have created same name test files as follows.
Code:
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214210500-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214211000-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214212000-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214211500-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214212500-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214213000-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214214000-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214213500-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214214500-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214215500-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214215000-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214220000-00000.cdr
-rw-r--r-- 1 Singh01 Singh01    0 Dec 24 01:13 bep01.smsc.191214220500-00000.cdr

Then following script may help in same.

Code:
cat move_files.ksh
default=92311
for j in "bep01.smsc.*"
do
        A=$j
done
for i in $A
do
        value=`echo $i | awk '{gsub(/\-.*/,X,$0);print}'`
        new_value=$value"-"$default"".cdr"
        mv $i $new_value
        echo file $i " has been renamed to " $value"-"$default".cdr"
        let "default = default + 1"
done

Output will be as follows after running the script.
Code:
./move_files.ksh
file bep01.smsc.191214210500-00000.cdr  has been renamed to  bep01.smsc.191214210500-92311.cdr
file bep01.smsc.191214211000-00000.cdr  has been renamed to  bep01.smsc.191214211000-92312.cdr
file bep01.smsc.191214211500-00000.cdr  has been renamed to  bep01.smsc.191214211500-92313.cdr
file bep01.smsc.191214212000-00000.cdr  has been renamed to  bep01.smsc.191214212000-92314.cdr
file bep01.smsc.191214212500-00000.cdr  has been renamed to  bep01.smsc.191214212500-92315.cdr
file bep01.smsc.191214213000-00000.cdr  has been renamed to  bep01.smsc.191214213000-92316.cdr
file bep01.smsc.191214213500-00000.cdr  has been renamed to  bep01.smsc.191214213500-92317.cdr
file bep01.smsc.191214214000-00000.cdr  has been renamed to  bep01.smsc.191214214000-92318.cdr
file bep01.smsc.191214214500-00000.cdr  has been renamed to  bep01.smsc.191214214500-92319.cdr
file bep01.smsc.191214215000-00000.cdr  has been renamed to  bep01.smsc.191214215000-92320.cdr
file bep01.smsc.191214215500-00000.cdr  has been renamed to  bep01.smsc.191214215500-92321.cdr
file bep01.smsc.191214220000-00000.cdr  has been renamed to  bep01.smsc.191214220000-92322.cdr
file bep01.smsc.191214220500-00000.cdr  has been renamed to  bep01.smsc.191214220500-92323.cdr

Kindly let me know if this helps.

Thanks,
R. Singh
Last edited by RavinderSingh13; 12-24-2014 at 02:56 AM.. Reason: Added a comment
# 7  
Old 12-24-2014
Quote:
Originally Posted by RavinderSingh13
Hello mfaizan40,

... ... ...

Code:
cat move_files.ksh
default=92311
for j in "bep01.smsc.*"
do
        A=$j
done
for i in $A
do
        value=`echo $i | awk '{gsub(/\-.*/,X,$0);print}'`
        new_value=$value"-"$default"".cdr"
        mv $i $new_value
        echo file $i " has been renamed to " $value"-"$default".cdr"
        let "default = default + 1"
done

... ... ...
Ravinder correctly notes that expanding the parameter list in a for statement avoids the possible argument list too long problem.

But:
  1. I don't understand the need for the 1st for loop.
  2. Calling awk 500 times seems like a lot of overhead when parameter substitution can be done in the shell without the overhead of invoking a separate process.
  3. There is a mismatched double quote in $value"-"$default"".cdr". Perhaps "$value-$default.cdr" is what was intended.
  4. While just expanding $default works fine as long as it starts out as a five digit number, it might be safer to use printf with a five digit leading zero filled format to cover the general case.
  5. It seems to be important to match the terminating -00000.cdr at the ends of the filenames in case other files starting with bep01.smsc. have already been renumbered.
  6. The let command is less portable than arithmetic substitution.

Taking the above considerations into account, you might want to also try something like:
Code:
#!/bin/ksh
sequence=92311
for i in bep01.smsc.*-00000.cdr
do	new="${i%00000.cdr}$(printf '%05d.cdr' "$sequence")"
	# mv $i $new
	echo "file $i has been renamed to $new"
	sequence=$((sequence + 1))
done

which will work with ksh, bash, or any other shell that performs POSIX standard parameter expansions and arithmetic substitutions.

If the echo statements show that the renaming calculations are correct, remove the # from the start of the mv command line so the script will actually move the files.
This User Gave Thanks to Don Cragun For This Post:
RavinderSingh13
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