Dear RudiC.
Thanks a lot for your help. it works fine but list all values which contents the status 14 and 98.
The work here is to get verify that the last index
Code:
ind=substr($0,26,1)
has a value of 1, if not them the script should list
Example
, is repeated 2 times = index 1, then again 2 times and the index increase to = 2, and ++
The goal here is to verify if the last index have code = 1, if not the case we need to list the errors.
For that from the input I should get this only.
Code:
6936919969 index 2 has 2 times status 14
6937919401 index 2 has 2 times status 14
6937919401 index 3 has 2 times status 14
6938720105 index 2 has 2 times status 14
6957719489 index 1 has 2 times status 98
6957719489 index 2 has 2 times status 98
6957719489 index 3 has 2 times status 98
6957719489 index 4 has 2 times status 98
6957919489 index 1 has 2 times status 98
6957919489 index 2 has 2 times status 98
6958119529 index 2 has 2 times status 14
6958320209 index 2 has 2 times status 14
6958719737 index 2 has 2 times status 14
6958920185 index 2 has 2 times status 14
6959120009 index 1 has 1 times status 98
6959320089 index 1 has 1 times status 98
Gents,
Using the following code i am able to output the information i need, but some of the strings are not complete due to the separator : used..
Kindly can u help me to get all string after the first :
Example in the output file column 16 i should get
17/11/25 03:43:51:732000
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BEGIN { printf ("CRYST1 200.000 200.000 200.000 90.00 90.00 90.00 P 1 1\n")
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natom=0
found_struct = 0
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}
{
if( NF == 5 )
{
foundff=0
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user_a blabla
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z=9
i=0
h=02
min=55
while
do
cat /home/barmecha/test | grep $h:$min >> /home/barmecha/file1
min=`expr $min + 1`
if ;
then
h=`expr $h + 1`
fi
i=`expr $i + 1`
done
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12-01-2014
