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awk - Why can't value of awk variables be passed to external functions ?

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Top Forums Shell Programming and Scripting awk - Why can't value of awk variables be passed to external functions ?
# 1  
Old 11-22-2014
As requested:
Code:
sudo ln -sf /bin/bash /bin/sh
echo "a/b/c/d/e" |
awk -F"/"       '{for (k=1;k<=NF;k++)   {if ($k == "a" )        {system("my_func_local " $k)}
                                         else                   {print $k}
                                        }
                 }
                '
In func a
b
c
d
e

Don't forget to recreate the original sh symlink.
Last edited by RudiC; 11-23-2014 at 09:31 AM.. Reason: typo
This User Gave Thanks to RudiC For This Post:
sreyan32
# 2  
Old 11-22-2014
Quote:
Originally Posted by RudiC
As required:
Code:
sudo ln -sf /bin/bash /bin/sh
echo "a/b/c/d/e" |
awk -F"/"       '{for (k=1;k<=NF;k++)   {if ($k == "a" )        {system("my_func_local " $k)}
                                         else                   {print $k}
                                        }
                 }
                '
In func a
b
c
d
e

Don't forget to recreate the original sh symlink.
Thanks. But can you tell me why did you need to create a symlink /bin/sh for this to work ? I mean whats the logic behind this. Why wasn't it working before ?
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