Shell Programming and Scripting

i'm trying to write a basic script that "watches" the apache access.log file and prints out lines that correspond to slow requests, Im checking for how microseconds it's taken. For the sake of testing, i'm using any number field.

so far I have:-

Code:

watch --interval=1 "tail access.log | cut -d ' ' -f2 "

that command will output the following e.g.

Code:

523
2334
22234
222
2234

I want to test each f2 field if it's greater than or less than a certain value I only want to output that field and ignore the rest, this is where I need help with, any feedback will be greatly appreciated.

thanks

Moderator's Comments:

Please use code tags next time for your code and data. Thanks

You should be able to run this without the watch:

Code:

tail -f access.log | awk '$2 >= MIN { print $2 }' MIN=1000 -

awk is like grep on steroids, with actual expressions and comparisons and if-then and columns. You find it on any UNIX system.

that's brilliant! thank you

now I have all those numbers I need saved in variable A, I want to add all those numbers up I want to show show (1) the average and (2) the maximum value, I'm getting stuck getting an average value

Code:

for i in $A; do
           echo item: $i
$sum=$sum+$i;
$i>=$maxValue
        done
echo $sum
echo $max

Code:

N=0
AVG=0
for I in $A
do
       let AVG=AVG+I
       let N=N+1
done

[ $N -gt 0 ] && let TOTAL=AVG/N