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Grep script name with path from crontab

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# 1  
Old 11-18-2014
Grep script name with path from crontab
I need help to grep file name with path from crontab
Code:
ex : 0 5 * * * /tmp/test.sh 2>/tmp/test.log

output : /tmp/test.sh



Moderator's Comments:
Mod Comment Please use code tags next time for your code and data. Thanks
Last edited by vbe; 11-18-2014 at 01:00 PM..
# 2  
Old 11-18-2014
Hi,

Quick & dirty;

Code:
crontab -l | awk '{ print $6 }'

Regards

Dave
# 3  
Old 11-18-2014
Code:
05,10,15.20,25,30 * *  * /tmp/test.sh 2>/tmp/test.log

does not work for above one
Last edited by vbe; 11-18-2014 at 01:01 PM.. Reason: code tags
# 4  
Old 11-18-2014
Because that line you gave is faulty... 05 is not the same as 0 5 ( 2 fields...)
The line you gave is missing the hour 05 belonging to the minutes...

in post#1 the line is correct...
# 5  
Old 11-18-2014
I am looking something like this start with first "/" and end with "2>"

Thanks

Johnny
# 6  
Old 11-18-2014
Code:
n12:/home/vbe/wks $ crontab -l|tail -1
# 05,10,15.20,25,30 * *  * /tmp/test.sh 2>/tmp/test.log
n12:/home/vbe/wks $ crontab -l | awk '{ print $6 }'|tail -1
/tmp/test.sh

Quote:
I am looking something like this start with first "/" and end with "2>"
Is that a new request?
if so open a new thread
# 7  
Old 11-19-2014
On a system with a standards conforming sed, the following should do what you requested:
Code:
crontab -l | sed -n 's|^[^/]*\(/[^[:space:]]*\)[[:space:]]*2>.*|\1|p'

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