Shell Programming and Scripting

# dd-mmm-yyyy
export FORMATTED_DATE=`date '+%d-%b-20%y'`
echo ${FORMATTED_DATE}

You may try this code:

#dt=21102004
read dt
let month="${dt:2:2}"
let month=$month*3-3
st="JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC"
echo "${dt:0:2}-${st:$month:3}-${dt:4:4}"

Regards
Sethu.

# !/bin/sh
mVar='17022006'
mYear=`echo $mVar | cut -c 5-8`
mMth=`echo $mVar | cut -c 3-4`
mDay=`echo $mVar | cut -c 1-2`
mAllMths='Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec'
mMthOut=`echo ${mAllMths} | cut -d' ' -f${mMth}`
echo ${mDay}'-'${mMthOut}'-'${mYear}

Try the above script; a simple shell script!

-ilan

Gaurav -

If you want a simple way to display the date as the format you want, You can go with this..,

Code:

DATE=`date +%d-%b-%Y`
echo $DATE

31-Aug-2007

Thanks..,

Sam.,

Try This .Simpler logic

month_mon='JAN+FEB+MAR+APR+MAY+JUN+JUL+AUG+SEP+OCT+NOV+DEC'
time_stamp='01012007' #Ur ddmmyyyy
dd=`echo $time_stamp|cut -c1-2`
mm=`echo $time_stamp|cut -c3-4`
yy=`echo $time_stamp|cut -c5-8`
file_mon=`echo ${month_mon}|cut -d"+" -f${mm}` #Gets ur month in MON
file_date=$dd'-'${file_mon}'-'${yy}
echo $file_date