Shell Programming and Scripting

Hi all

I am trying to create a script that takes a password input then writes that to a tmp file and puts that tmp file path in my env as a var.

It does everything but export the my env and I am unsure why.

I am using Ubuntu 12.4

Code:

#!/bin/bash

read -s -p "Enter Password: " gfpassword

TMP=`tempfile`

echo "AS_ADMIN_PASSWORD=$gfpassword" > $TMP

GF=$TMP

export GF

Any help would be fantastic and thank you

Code:

TMP=`tempfile`

The back ticks are to execute a program name tempfile and assign its output to a variable name TMP.

This would be what you want.

Code:

TMP="/path/to/tempfile"

Thank you.

I made the following change and if I do a echo on $GF it definitely shows me the path to the temp file created however it still isn't add $GF to the environment variables

Code:

#!/bin/bash

read -s -p "Enter Password: " gfpassword

TMP="$(tempfile)"

echo "AS_ADMIN_PASSWORD=$gfpassword" > $TMP

GF=$TMP

echo $GF

export GF

Code:

glass@xxxxxxx:~/scripts$ ./rbtest.sh 
Enter Password: /tmp/fileZo2wDX

Edited: Not clear of what its wanted. Sorry.

No Aia, that is wrong.

koikoi, remember that environment variables are inherited from parent processes to child processes. The environment is never actually shared, just copied. Children receive copies when they are created.

When you run a script with ./script or /path/to/script you are creating a new child process to run it in. The variable gets exported just fine in this new child. It then finishes and quits, returning to your parent process which of course remains unchanged.

To export it in your own shell, you must run it in your own shell, called "sourcing" it. The operator for source is "dot space filename", i.e. . ./script.sh

Thank you so much ... I have been fighting this for a few hours.