This is using perl regex's lazy matching operator, .*? means a lazy (minimal) match of characters..
The assymetrical enclosing characters use a separate substitution command for each pair. In this case there are only parentheses. In the substitute command they are preceded by backslashes to use their literal meaning.
For the symmetrical enclosing characters in the second substution command, a backreference \1 is used to match the previously matched attribute from the enclosing characters class, in this case either * or ", but any number of characters can be added inside the square brackets. The character class is within parentheses (...)so it can be backreferenced later.
It can also be written more compactly:
using alternation (|)
If it is only these three cases then perhaps this is preferable:
Since it is somewhat easier to read..
Output:
--
For multiline sequences you could use:perl -00pe ....., or perl -0077pe .....so for example:
Last edited by Scrutinizer; 11-14-2014 at 01:45 AM..
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Hi Team ,
I want supress the meaning of * while passing it as parameter.
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func1 ()
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Hi All
this is a simple script
#! /bin/bash
FileCnt=`ls -lrt $DIR/* | wc -l`
echo $FileCnt
how could i escape the error msg if there are no files in $DIR
ls: /home/sayantan/test/files/cnt/*: No such file or directory
0
Looking forward for a quick reply
Regards, Newbie (2 Replies)
I am using this command
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