Shell Programming and Scripting

Hi,

I have a script invest.sh which takes two inputs i.e the name of the properties file and the file permissions for eg:

Code:

./invest.sh app12.properties 664

Now i wish to give a folder path /opt/app/properties instead of the properties file and the invest.sh script should lookout for all the files with the .properties extension in all the sub-directories and run the script for all the properties instead of single.

for eg:

Code:

./invest.sh /opt/app/properties 664

I m aware of the find command however, can you help me with teh snippet which will help me achieve this ?

Did you consider the -R option of chmod?

When you use:

Code:

chmod -R 664 directory

it changes the mode of the named directory and all files in the hierarchy below it.

To just change the mode of regular files with names ending with .properties in a hierarchy, try:

Code:

find directory -name '*.properties' -type f -exec chmod 664 '{}' +

As Don Cragun already suggested use find with the -exec-clause:

Code:

find /path/to/directory -type -f -name "*.properties" -exec invest.sh {} <filemode> \;

But maybe you want to extend your script to do that automatically. Notice, in this case, that there is no difference between file names and directory names. You will have to use test -d and/or test -f to test for files or directories, like this:

Code:

if   [ -f "$1" ] ; then
     old_invest.sh "$1" "$2"
elif [ -d "$1" ] ; then
     find "$1" -type f -name "*.properties" -exec old_invest.sh {} $2 \;
else
     echo "Error: specify only directories or files." >&2
fi

I hope this helps.

bakunin