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Finding file extension on C Shell script

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Top Forums Shell Programming and Scripting Finding file extension on C Shell script
# 1  
Old 11-06-2014
Finding file extension on C Shell script
I very new to C Shell. I am trying to do is read from Command line.
Find the if the file is zip, .txt, symbloic link,pipe, unknow (if file is not zip, txt, sy....)
here is what I what got so far. I am very stuck atm Please help me out :


If the file is symblooc link what file is link to

Code:
!/bin/csh

if ( "echo ${1} | cut -d'.' -f2" == "zip" )  then
   echo $1 is a zip file
else
   echo sorry, $1 is not a zip file
endif


Moderator's Comments:
Mod Comment Please use code tags next time for your code and data. Thanks


---------- Post updated at 11:15 AM ---------- Previous update was at 11:04 AM ----------

Can someone help me out here?
# 2  
Old 11-06-2014
Look for case statement, Why use csh?
# 3  
Old 11-06-2014
Quote:
Originally Posted by madbull41
I very new to C Shell. I am trying to do is read from Command line.
Find the if the file is zip, .txt, symbloic link,pipe, unknow (if file is not zip, txt, sy....)
here is what I what got so far. I am very stuck atm Please help me out :


If the file is symblooc link what file is link to

Code:
!/bin/csh

if ( "echo ${1} | cut -d'.' -f2" == "zip" )  then
   echo $1 is a zip file
else
   echo sorry, $1 is not a zip file
endif

Moderator's Comments:
Mod Comment Please use code tags next time for your code and data. Thanks


---------- Post updated at 11:15 AM ---------- Previous update was at 11:04 AM ----------

Can someone help me out here?
The file name is irrelevant - the data inside the file is the data inside the file.
# 4  
Old 11-06-2014
We use C Shell atm. Here is more clear information C shell script print information about filespace objects.
# 5  
Old 11-06-2014
Your code can be optimized like this:
Code:
#!/bin/csh
if ( "${1:e}" == "zip" ) then
  echo "$1 is a zip file"
else
  echo "sorry, $1 is not a zip file"
endif

A "case" statement in C-shell looks like this
Code:
switch ( "${1:e}" )
case zip:
  echo "$1 is a zip file"
  breaksw
case zap:
  echo "$1 is a zap file"
  breaksw
default:
  echo "sorry, $1 is neither a zip nor a zap file"
endsw

# 6  
Old 11-06-2014
Quote:
Originally Posted by MadeInGermany
Your code can be optimized like this:
Code:
#!/bin/csh
if ( "${1:e}" == "zip" ) then
  echo "$1 is a zip file"
else
  echo "sorry, $1 is not a zip file"
endif

A "case" statement in C-shell looks like this
Code:
switch ( "${1:e}" )
case zip:
  echo "$1 is a zip file"
  breaksw
case zap:
  echo "$1 is a zap file"
  breaksw
default:
  echo "sorry, $1 is neither a zip nor a zap file"
endsw

"${1:e}"
what is mean?

$1 is command line right?
Code:
switch ( "${1:e}" )
case txt:
  echo "$1 is text"
  breaksw
case zap:
  echo "$1 is text"
  breaksw
default:
  echo "sorry, $1 is neither a zip nor a zap file"
endsw

[/QUOTE]

I mean in simple folder there just not one file in there. There will be a lot of file like txt pipe and all thing i mention above!
# 7  
Old 11-06-2014
$1 is the first argument when one runs the script (on the command line or from another script), for example
Code:
./yourscript example.zip

${1:e} is the "filename extension" i.e. the part after the last dot (and file type in Windos).
The e is a modifier. See
Code:
man csh

for other modifiers.
C-shell wants to expand/match/substitute a $variable so always quote it "$variable". Or, more general, have them in quotes like the following two variables
Code:
echo "$var1 and ${var2:e}"

NB you need the braces if you use a modifier. Without a modifier you can still use braces: echo "${var1}"
Last edited by MadeInGermany; 11-06-2014 at 01:55 PM.. Reason: code tag missing
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